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nlexa [21]
1 year ago
15

What evidence supports the existence of a very massive black hole at the center of our galaxy?

Physics
1 answer:
faltersainse [42]1 year ago
5 0

<u>The motions of the gas and stars at the center indicate that it contains 4 million solar masses within a region no larger than our solar system</u> is the evidence supports the existence of a very massive black hole at the center of our galaxy.

<h3>What is black hole?</h3>

Black holes are points in space that are so dense they create deep gravity sinks. Beyond a certain region, not even light can escape the powerful tug of a black hole's gravity. And anything that ventures too close—be it star, planet, or spacecraft—will be stretched and compressed like putty in a theoretical process aptly known as spaghettification.

There are four types of black holes: stellar, intermediate, supermassive, and miniature. The most commonly known way a black hole forms is by stellar death. As stars reach the ends of their lives, most will inflate, lose mass, and then cool to form white dwarfs. But the largest of these fiery bodies, those at least 10 to 20 times as massive as our own sun, are destined to become either super-dense neutron stars or so-called stellar-mass black holes.

Learn more about black holes

brainly.com/question/13002947

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4. A high school athlete runs 400 m in 52.20 sec. What is his speed in mph?<br> 14100<br> 1110
Serggg [28]

Answer:

28,800m/p second

Explanation:

Calculate the distance per second so, 400m/50 s= 8m/p second now knowing the speed/hour and knowing an hour has 3,600 seconds,multiply it by 8 then you will get 28,800m/p second, or 28.8km/h

3 0
2 years ago
Need help ASAP please helppp
Setler [38]

Answer:

2.3 newtons of force

Explanation:

Divide the weight by the speed of the bike

4 0
3 years ago
What is the energy of a photon of this light, in ev ?
Stels [109]
U7g19xuih;8weoxhwe8ou1whuowxhw
7 0
3 years ago
A light has a wavelength of 5.06x10-7m. what is the frequency of the light?
Artyom0805 [142]

So, the frequency of that light approximately \sf{\bold{5.93 \times 10^{14} \: Hz}}

<h3>Introduction</h3>

Hi ! Here I will help you to discuss the relationship between frequency and wavelength, with the velocity constant of electromagnetic waves in a vacuum. We all know that regardless of the type of electromagnetic wave, it will have the same velocity as the speed of light (light is part of electromagnetic wave too), which is 300,000 km/s or \sf{3 \times 10^8} m/s. As a result of this constant property, <u>the shorter the wavelength, the greater the value of the electromagnetic wave frequency</u>. This relationship can also be expressed in this equation:

\boxed{\sf{\bold{c = \lambda \times f}}}

With the following condition :

  • c = the constant of the speed of light in a vacuum ≈ \sf{3 \times 10^{8} \: m/s} m/s
  • \sf{\lambda} = wavelength (m)
  • f = electromagnetic wave frequency (Hz)

<h3>Problem Solving</h3>

We know that :

  • c = the constant of the speed of light in a vacuum ≈ \sf{3 \times 10^{8} \: m/s} m/s
  • \sf{\lambda} = wavelength = \sf{5.06 \times 10^{-7}} m.

What was asked :

  • f = electromagnetic wave frequency = ... Hz

Step by step :

\sf{c = \lambda \times f}

\sf{3 \times 10^8 = 5.06 \times 10^{-7} \times f}

\sf{f = \frac{3 \times 10^8}{5.06 \times 10^{-7}}}

\sf{f \approx 0.593 \times 10^{8 - (-7)}}

\sf{f \approx 0.593 \times 10^{15}}

\boxed{\sf{f \approx 5.93 \times 10^{14} \: Hz}}

<h3>Conclusion :</h3>

So, the frequency of that light approximately \sf{\bold{5.93 \times 10^{14} \: Hz}}

<h3>See More :</h3>
  • What affects photon energy brainly.com/question/26434060
  • What is the foton energy brainly.com/question/26518899
7 0
2 years ago
an 80 kg cart goes around the inside of a vertical loop of a roller coaster. the radius of the loop is 5m and the cart moves at
GarryVolchara [31]

Answer:

F=  224 N

Explanation:

Given that

mass ,m = 80 kg

Radius ,r= 5 m

speed at the top v= 8 m/s

The force at the top = F

Now by using the Second law of Newton's

F+mg=\dfrac{mv^2}{r}

Now by putting the values

F+80\times 10 = \dfrac{80\times 8^}{5}

Take  g = 10 m/s²

F= \dfrac{80\times 8^2}{5}-800

F=  224 N

Therefore the force exerted by the track at the top position will be 224 N.

3 0
3 years ago
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