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kkurt [141]
4 years ago
5

An illustration of a nuclear reactor. There are 3 parallel lines sticking half out of the reactor labeled rods containing uraniu

m. There are parallel rods in the reactor labeled neutron-absorbing material. It is labeled nuclear reactor.
A power plant needs to slow down the fission reactions in its nuclear reactor. In which direction should the uranium-containing rods in the diagram be moved?

left
right
up
down
Physics
2 answers:
hodyreva [135]4 years ago
7 0

Answer:

D) down

Explanation:

I guess it and got it right :)

Stolb23 [73]4 years ago
5 0

Answer:

down

Explanation:

just did it on edge

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You stand on a straight desert road at night and observe a vehicle approaching. This vehicle is equipped with two small headligh
spayn [35]

To solve this problem we will apply the concepts related to Reyleigh's criteria. Here the resolution of the eye is defined as 1.22 times the wavelength over the diameter of the eye. Mathematically this is,

\theta = \frac{1.22 \lambda }{D}

Here,

D is diameter of the eye

D = \frac{1.22 (539nm)}{5.11 mm}

D= 1.287*10^{-4}m

The angle that relates the distance between the lights and the distance to the lamp is given by,

Sin\theta = \frac{d}{L}

For small angle, sin\theta = \theta

sin \theta = \frac{d}{L}

Here,

d = Distance between lights

L = Distance from eye to lamp

For small angle sin \theta = \theta

Therefore,

L = \frac{d}{sin\theta}

L = \frac{0.691m}{1.287*10^{-4}}

L = 5367m

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4 0
4 years ago
A heater has a resistance of 10.0 Ω. It operates on a 12.0 V. What is the current through the resistor?
irakobra [83]

Answer:

1.2 amps :)

Explanation:

A heater has a resistance of 10.0 Ω. It operates on a 12.0 V. What is the current through the resistor?

         Known:

  • R = 10.0 Ω                            
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       Unknown:

  • I = ???

I = V/R

= 12.0 V / 10.0 Ω

= 1.2 amps

6 0
3 years ago
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astra-53 [7]

Answer:

1968

Explanation:

2400*20.5*0.004

8 0
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Answer:

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Explanation:

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