Answer:
54mph
Explanation:
Speed is defined as the change in distance of a body with respect to time.
Let x be the speed of Eric on his way to the football game, if he used 11hours to the football game, his distance will be the product of his speed and time taken i.e
Distance = speed × time
Distance= x × 11
Distance = 11x... (1)
During his return journey, his speed increases by 12mph with a return drive in only 9hours i.e speed = x+12 and time is 9hours
Since distance = speed × time (return Journey)
Distance = (x+12)×9
Distance = 9x+84...(2)
Note that the distance to and fro the journey is the same as such we will equate equations 1 and 2 to get his initial speed "x" to have;
11x = 9x+84
11x-9x = 84
2x = 84
x = 42mph
This means that his initial speed on his way to the football game is 42mph. Since his speed increases by 12mph during his return drive, his return speed will be 42mph + 12mph which gives 54mph.
Answer: 4.speed
Explanation:
In this case, we know that the cart remains at a constant 20km/h.
Now, one could say that "the velocity remains constant, because it always is 20km/h"
But remember that velocity is a vector, so this has a direction, and if the cart is going around a turn, then the direction of motion is changing, which tell us that there is acceleration.
But the module of the velocity, the speed, remains constant at 20km/h.
Then the correct option is 4, speed.
Answer:
im sure your already past this but it's E.
Explanation:
This is because in this case potential energy is linear to height, which means that the higher the more potential energy.
Answer:
The final speed of the bicyclist is 15.44 m/s.
Explanation:
Given;
initial velocity, u = 0
time of motion, t = 4.8 s
distance covered, d = 37.0 m
The acceleration of the bicyclist is calculated as;
d = ut + ¹/₂at²
37 = 0 + ¹/₂(4.8)²a
37 = 11.52a
a = 37 / 11.5
a = 3.22 m/s²
The final speed of the bicyclist is given as;
v² = u² + 2ad
v² = 0 + 2(3.22)(37)
v² = 238.28
v = √238.28
v = 15.44 m/s
Therefore, the final speed of the bicyclist is 15.44 m/s.
