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3 years ago

For life to flourish on Earth, several changes occurred that affected the atmosphere, such as _____.

1 answer:

8 0

Evolution of cyanobacteria that produce O2volcanic outgassing to create a thicker atmosphereformation of an ozone layer to block harmful radiationall of the aboveonly a and c

Are the options

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A 90 kg person stands at the edge of a stationary children's merry-go-round at a distance of 5.0 m from its center. The person s

Paraphin [41]

Answer:

$\omega = 0.016\,\frac{rad}{s}$

Explanation:

The rotation rate of the man is:

$\omega = \frac{v}{R}$

$\omega = \frac{0.80\,\frac{m}{s} }{5\,m}$

$\omega = 0.16\,\frac{rad}{s}$

The resultant rotation rate of the system is computed from the Principle of Angular Momentum Conservation:

$(90\,kg)\cdot (5\,m)^{2}\cdot (0.16\,\frac{rad}{s} ) = [(90\,kg)\cdot (5\,m)^{2}+20000\,kg\cdot m^{2}]\cdot \omega$

The final angular speed is:

$\omega = 0.016\,\frac{rad}{s}$

3 0

3 years ago

If i = 1.70 A of current flows through the loop and the loop experiences a torque of magnitude 0.0760 N ⋅ m , what are the lengt

Alik [6]

Answer:

Length of the sides of the square loop is given by

s = √[(τ)/(NIB sin θ)]

Explanation:

The torque, τ, experienced by a square loop of area, A, with N number of turns around the loop and current of I flowing in the wire, with a magnetic field presence, B, and the plane of the loop tilted at angle θ to the x-axis, is given by

τ = (N)(I)(A)(B) sin θ

If everything else is given, the length of a side of the square loop, s, can be obtained from its Area, A.

A = s²

τ = (N)(I)(A)(B) sin θ

A = (τ)/(NIB sin θ)

s² = (τ)/(NIB sin θ)

s = √[(τ)/(NIB sin θ)]

In this question, τ = 0.076 N.m, I = 1.70 A

But we still need the following to obtain a numerical value for the length of a side of the square loop.

N = number of turnsof wire around the loop

B = magnetic field strength

θ = angle to which the plane of the loop is tilted, measured with respect to the x-axis.

6 0

3 years ago

Read 2 more answers

Derive the formula v= u+ at please derive in detail

gogolik [260]

Lets do

We know

The rate of change of velocity is acceleration .

$\\ \sf\longmapsto a=\dfrac{dv}{dt}$

$\\ \sf\longmapsto dv=adt$

Integrate both sides

$\\ \sf\longmapsto \int dv=a\int dt$

As acceleration is constant .Take it outside of integral .On velocity we can take limit u to v and time from 0 to t

$\\ \sf\longmapsto {\displaystyle{\int}}^v_u dv=a{\displaystyle{\int}}^t_0 dt$

Hence

$\\ \sf\longmapsto v{\huge{|}}^v_u=at$

$\\ \sf\longmapsto v-u=at$

$\\ \sf\longmapsto v=u+at$

4 0

3 years ago

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A particle moves along the x axis according to the equation x = 6t², where x is in meters and t is in seconds. Therefore:

vladimir2022 [97]

Answer is E

time can be negative.
A is not true because a=d2xdt2=12 m/s2
C: question already said that particle move along x-axis, which is not parabola path.
D: velocity is dxdt=12t, therefore velocity changes by 12 m/s and not 9.8 m/s
So we are left with E.

7 0

3 years ago

What determines the pitch of a sound wave

saveliy_v [14]

Frequency of the wave " the loudness"

4 0

3 years ago

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