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3 years ago

How many grams of NaoH are needed to nutralize 50 grams of H2SO4?

1 answer:

6 0

to neutralize 1 mole of H2 S o4 we need one mole of any if we are having 50 grams of H2 S o4 it means the mole of H2 S o4 in 50 gram will be 50×40)/98 hence

utilising 50 grams of H2 S o4 we need approximately 20. 5 gm of Naoh

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A gas is heated from 263.0 K to 298.0 K and the volume is increased from 24.0 liters to 35.0 liters by moving a large piston wit

Evgesh-ka [11]

Answer:

The answer to your question is P2 = 0.78 atm

Explanation:

Data

Temperature 1 = T1 = 263°K Temperature 2 = T2 = 298°K

Volume 1 = V1 = 24 L Volume 2 = V2 = 35 L

Pressure 1 = P1 = 1 Pressure 2 = P2 = ?

Process

1.- To solve this problem use the Combined gas law

P1V1/T1 = P2V2/T2

-Solve for P2

P2 = P1V1T2 / T1V2

-Substitution

P2 = (1)(24)(298) / (263)(35)

-Simplification

P2 = 7152 / 9205

-Result

P2 = 0.777

or P2 = 0.78 atm

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PV=nRT

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Hence for clorine

n=0.441mol

Given the reaction

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How many grams of NaoH are needed to nutralize 50 grams of H2SO4?​

How many grams of NaoH are needed to nutralize 50 grams of H2SO4?