Answer:
0.017 mol
Explanation:
CH3COOH - acetic acid - we can write as C2O2H4
From formula C2O2H4 we can see that ratio C: O = 2:2 = 1:1, so number of moles C and O are the same.
So if we have 0.017 mol C, we should have 0.017 mol O.
Explanation:
Litmus paper is your answer
please mark as brilliant
Given ,
Mass of sample of cobalt = 27 g
density of sample of cobalt = 9g/cm^3
We know that ,
Density = mass of sample/volume of sample
From that relation ,
We can deduce the following as
Volume = mass of sample/density of sample
Hence , required volume of sample of cobalt = 27 g /9 g/cm^3 = 3 cm^3
The volume is
Answer:
segment 4
Explanation:
Its segment 4 because even though they only traveled 55(km) its only been 1 hour. Every other one took ether 1 hour and 5 minutes or 2 hours.(this is my honest opinion im sorry if its wrong)