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kkurt [141]
3 years ago
6

!! HELP !!

Physics
1 answer:
masha68 [24]3 years ago
8 0

Answer:

18301.4Kg

Explanation:

Step 1:

Data obtained from the question. This include the following:

Mass 1 (M1) = 0.512Kg

Mass 2 (M2) =..?

Distance apart (r) = 0.0250m

Force (F) = 0.001N

Gravitational force constant (G) = 6.67x10^-11Nm²/Kg²

Step 2:

Determination of the mass, M2 needed to create a force of 0.001N.

This can be obtained as follow:

F = GM1M2/r²

0.001 = 6.67x10^-11 x 0.512 xM2/0.025²

Cross multiply

6.67x10^-11 x 0.512 xM2 = 0.001x0.025²

Divide both side by 6.67x10^-11 x 0.512

M2 = (0.001x0.025²)/(6.67x10^-11x0.512)

M2 = 18301.4Kg

Therefore, a mass of 18301.4Kg is needed

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A gumdrop is released from rest at the top of the empire state building, which is 381 m tall. disregarding air resistance, calcu
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<u>Answer:</u>

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  Velocity after 3 seconds = 29.4 m/s

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We have equation of motion , s= ut+\frac{1}{2} at^2, s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

 Height of building, displacement = 381 meter

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 Displacement after 1 second = 0*1+\frac{1}{2}*9.8*1^2=4.9m

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 Displacement after 3 seconds = 0*3+\frac{1}{2}*9.8*3^2=44.1m

We have equation of motion, v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time taken.

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  Velocity after 3 seconds = 0 + 9.8 * 3 = 29.4 m/s

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The formula we can use here is:

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