speed Δv = v₂ = 8.15ms⁻¹
v₁ = 0ms⁻¹
time =t = 5s
acceleration = a = speed / time taken
a = Δv / Δt ( as Δv = v₂ - v₁)
a = 8.15ms⁻¹ / 5 s
a = 1.6ms⁻²
Answer:
Height, h = 10.20 meters
Explanation:
It is given that,
Mass of the object, m = 3 kg
Energy of object, E = 300 J
Let it will moved to a height of h. The energy possessed by it is called gravitational potential energy. It is given by :



h = 10.20 meters
So, the object will move to height of 10.20 meters. Hence, this is the required solution.
Distance to the moon = 4×
m.
1 m = 3.28 ft
Distance to the moon in ft = 4×
×3.28 ft
= 13.12 ×
ft
1 fathom = 6 ft
Hence, distance to the moon in fathom
=
×
≈ 2×
fathom
Answer:
B
Explanation:
The impulse experienced by an object is the force•time.
I'm going to assume this is over a horizontal distance. You know from Newton's Laws that F=ma --> a = F/m. You also know from your equations of linear motion that v^2=v0^2+2ad. Combining these two equations gives you v^2=v0^2+2(F/m)d. We can plug in the given values to get v^2=0^2+2(20/3)0.25. Solving for v we get v=1.82 m/s!