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Zarrin [17]
3 years ago
11

Electromagnetic waves are ____________ (one thousand/one million) times faster than sound.

Physics
2 answers:
spayn [35]3 years ago
5 0

Electromagnetic waves in air are 874,000 times as fast as sound waves.

I guess that's closer to <em>one million</em> than it is to one thousand.

vesna_86 [32]3 years ago
3 0

Answer:

one million

Explanation:

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A rock dropped on the moon will increase its speed from 0m/s to 8.15 m/s in 5 seconds what is the acceleration of the rock
sergejj [24]

speed  Δv     =  v₂ =  8.15ms⁻¹

                     v₁ = 0ms⁻¹

time  =t = 5s

acceleration  =  a = speed / time taken

                          a =    Δv / Δt           ( as Δv = v₂ - v₁)

                          a  =   8.15ms⁻¹  /  5 s

                            a  = 1.6ms⁻²

                               

3 0
4 years ago
How high up is a 3 kg object that has 300 joules of energy
kvasek [131]

Answer:

Height, h = 10.20 meters

Explanation:

It is given that,

Mass of the object, m = 3 kg

Energy of object, E = 300 J

Let it will moved to a height of h. The energy possessed by it is called gravitational potential energy. It is given by :

E=mgh

h=\dfrac{E}{mg}

h=\dfrac{300\ J}{3\ kg\times 9.8\ m/s^2}

h = 10.20 meters

So, the object will move to height of 10.20 meters. Hence, this is the required solution.

5 0
4 years ago
Read 2 more answers
A fathom is a unit of length about 6 ft long commonly used in measuring depths of water. Because a fathom is about the length of
Naddik [55]

Distance to the moon = 4×10^{8}m.

1 m = 3.28 ft

Distance to the moon in ft = 4×10^{8}×3.28 ft

= 13.12 ×10^{8}ft

1 fathom = 6 ft

Hence, distance to the moon in fathom

= \frac{13.2}{6}×10^{8}

≈ 2× 10^{8}fathom



4 0
4 years ago
Impulse equals?<br> A) momentum x velocity<br> B) momentum x time<br> C) mass x velocity
mina [271]

Answer:

B

Explanation:

The impulse experienced by an object is the force•time.

7 0
3 years ago
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In Figure 10-1, if the force exerted on a 3.0-kg backpack that is initally at rest is 20.0 N and the distance it acts over is 0.
pshichka [43]
I'm going to assume this is over a horizontal distance. You know from Newton's Laws that F=ma --> a = F/m. You also know from your equations of linear motion that v^2=v0^2+2ad. Combining these two equations gives you v^2=v0^2+2(F/m)d. We can plug in the given values to get v^2=0^2+2(20/3)0.25. Solving for v we get v=1.82 m/s!
4 0
3 years ago
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