HELP THIS IS FOR CHEM!! If the pull force is 898N and the friction force is 335N what is the net force?

What is the standard unit that astronomers use to measure the size of a star

g100num [7]

Parsecs or abbreviated pc

7 0

3 years ago

The dehydration of the alcohol functional group is a widely used reaction in organic chemistry. The mechanism is generally accep

puteri [66]

Answer:

Elimination
Elimination
Zaitsev
Zaitsev
Carbocation

Explanation:

The mechanism is generally accepted to always operate via an ELIMINATION step-wise process.

The ELIMINATION mechanism process will always produce (after dehydration) a ZAITSEV style alkene as major product

The driving force for the production of this ZAITSEV style alkene product is generally going to be determined by stability of the CARBOCATION

Elimination mechanism is the removal of two substituents from a molecule in either a one- or two-step mechanism

Carbocation is a molecule containing a positive charged carbon atom and three bonds

3 0

2 years ago

How are flash drives better than hard drives

Greeley [361]

Flash drivers are more robust, if you drop it, it is still most likely to work. Hard drivers provide more storage. There’s not much difference

8 0

3 years ago

The shielding of electrons gives rise to an effective nuclear charge, Zeff, which explains why boron is larger than oxygen. Esti

Vesna [10]

Zeff = Z - S

Here, Z is the number of protons in the nucleus, that is, atomic number, and S is the number of nonvalence electrons.

For boron, the electronic configuration is 1s₂ 2s₂ 2p₄

Z = 5, S = 2

Zeff = 5-2 = +3

For O, electronic configuration is 1s₂ 2s₂ 2p₄

Z = 8, S = 2

Zeff = 8-2 = +6

Hence, the correct answer is second option, that is, +3 and +6, the Zeff of boron is smaller in comparison to O, thus, boron exhibits a bigger size than O.

3 0

3 years ago

Rank the compounds in each set in order of increasing acid strength.

Viktor [21]

Answer:

See explanation

Explanation:

For this question, we have to remember the effect of an atom with high electronegativity as "Br". If the "Br" atom is closer to the carboxylic acid group (COOH) we will have an inductive effect. Due to the electronegativity of Br, the electrons of the C-H bond would be to the Br, then this bond would be weaker and the compound will be more acid (because is easier to produce the hydronium ion $H^+$ ).

With this in mind, for A in the last compound, we have 2 Br atoms near to the acid carboxylic group, so, we will have a high inductive effect, then the C-H would be weaker and we will have more acidity. Then we will have the compound with only 1 Br atom and finally, the last compound would be the one without Br atoms.

In B, the difference between the molecules is the position of the "Br" atom in the molecule. If the Br atom is closer to the acid group we will have a higher inductive effect and more acidity.

See figure 1

I hope it helps!

5 0

3 years ago