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Vesnalui [34]
3 years ago
13

Consider a cylindrical crew module with a diameter of 5 meters, a length of 15 meters, and a crew of 6 people. The module contai

ns air that is at
standard sea-level atmospheric pressure and temperature. The sea level density of air at 20 degrees Celsius is 1.204 kg/m3.
What is the volume of the crew module? Provide your answer in m' with at least 2 decimal places.​
Physics
1 answer:
UNO [17]3 years ago
7 0

Answer:

  294.524 m^3

Explanation:

The volume of a cylinder is given by the formula ...

  V = πr^2h

For a radius of 2.5 m and a length of 15 m, the volume is ...

  V = π(2.5 m)^2(15 m) = 93.75π m^3 ≈ 294.524 m^3

The volume is about 294.52 cubic meters.

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The device used to measure a masses of a body is kilogram . true or false​
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Answer: false

Explanation:

While kilograms are the unit used to measure body mass, the device used is a scale.

Hope it helps :)

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2 years ago
In the electromagnetic spectrum, _______ is the _______ frequency color of visible light.
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In the electromagnetic spectrum, "Blue" is the "highest" <span>frequency color of visible light.

Or I</span>n the electromagnetic spectrum, "Red" is the "Lowest" frequency color of visible light.

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Marysya12 [62]
When acid reacts with water, the hydroxide ion is formed I think it is true.
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sergey [27]

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5 0
2 years ago
Read 2 more answers
An object of mass 180 g initially at rest explodes into three pieces. One piece has mass 70 g and moves directly west at speed 1
Aleonysh [2.5K]

Answer: the speed is 22.17m/s, and the direction is 42.56° from north to east.

Explanation:

The mass of the object is 180g, and it initialy has a velocity of 0m/s, so the total momentum is P = 0

In this problem we must use the conservation of the momentum, this means that the final momentum must be equal than the initial momentum.

we have 3 pieces:

One has a mass of m1 = 70g and v1 = 14m/s west.

other has a mass of m2 = 50g and v2 = 18m/s south.

this two pieces have a momentum of:

p1 = 70*14 (g*m/s) west = 980 (g*m/s) west

p2 = 50*18 (g*m/s) south = 900 (g*m/s) south.

now, the total momentum must be zero, so P3 = 980  (g*m/s)  east + 900 ( (g*m/s) north.

first, knowing that the total mass is 180g, we have that the mass of the third piece is:

m3 = 180g - 70g - 50g = 60g

now, for the momentum we will have that one component goes north and other east, if we define the angle A as the angle that goes from north to east (such that A = 0° means that we are moving directly to north) we will have:

p3 = 60g*v*(cos(A)) to north + 60g*v*sin(A)

then we have a system of equations:

60*v*cos(A) = 980

60*v*sin(A) = 900

Here we can use the quotient of equation 2 and equation 1, in this way we remove the variable v and we can solve it for A:

(60*v*sin(A) )/(60*v*cos(A)) = 900/980

tan(A) = 900/980

Atan(tan(A)) = A = Atan(900/980) = 42.56°

now with this angle we can find the value of v:

60*v*cos(42.56°) = 980

v = 980/(60*cos(42.56°) = 22.17 m/s

then the speed is 22.17m/s, and the direction is 42.56° from north to east.

7 0
3 years ago
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