Answer:
0.0018 mol/min is the average rate of carbon dioxide gas production in moles per minute during the 10 minutes.
Explanation:
Pressure of carbon dioxide gas = P = 0.25 atm
Volume of carbon dioxide gas = V = 5.0 L
Moles of carbon dioxide gas = n
Temperature of the carbon dioxide gas,T = 550°C = 550+273 K = 823 K
Using an ideal gas equation :
n = 0.018 mol
In 10 minutes pressure of carbon dioxide gas reached to 0.25 atm
Average rate of production of moles of carbon dioxide gas per minute in duration of 10 minutes:
0.0018 mol/min is the average rate of carbon dioxide gas production in moles per minute during the 10 minutes.
Answer
:yes or no
Explanation:
you needd tol try it yolurself
Answer:
Explanation:
It starts with the company getting a GS1 Company Prefix Before a firm starts to use a barcode it has to come up with the GS1 Identification Keys which are the numbers that represent the company’s barcode. When the GS1 identification key is assigned, the firm acquires the GS1 Company Prefix that will enable the firm to create the identification keys for its goods, locations, trade items and coupons which will be unique to it worldwide.
Liquid - rain
Solid - snow
Gas - water vapour (when it evapourates from the lithosphere)
Answer: 8.45 L
Explanation:
Given that,
Initial volume (V1) = 3.5L
Initial pressure (P1) = 2.5 atm
[Since final pressure is given in torr, convert 2.5 atm to torr
If 1 atm = 760 torr
2.5 atm = 2.5 x 760 = 1900 torr
Final volume (V2) = ?
Final pressure (P2) = 787 torr
Since pressure and volume are given while temperature remains the same, apply the formula for Boyle's law
P1V1 = P2V2
3.5L x 1900 torr = 787 torr x V2
6650L•torr = 787 torr•V2
Divide both sides by 787 torr
6650L•torr/787 torr = 787 torr•V2/787 torr
8.45 L = V2
Thus, the volume of the gas at 787 torr and at the same temperature is 8.45 Liters
