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pshichka [43]
3 years ago
5

Which actions are part of a system of methodical tests and refinements specific to technological design?

Physics
2 answers:
jarptica [38.1K]3 years ago
7 0

Answer:

B. tinkering, presenting, testing

Explanation:

In technological designs, some actions that are part of a system of methodical tests are grouped as technological process. Technological process is defined as the ordered procedure or steps to be followed in order to successfully accomplish a task (e.g project).

The project must have been created and refined i.e tinkered to ensure it gives an expected result or outcome i.e the project should give a solution to the problem that it was designed for. Which would undergo presentation and testing before it can be approved.

KATRIN_1 [288]3 years ago
4 0

Answer:

Documenting, Tinkering, Testing

Explanation:

plz give brainliest

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Which equation describes the sum of the two vectors plotted below?
dem82 [27]

Answer:

R=-x-4y

Explanation:

Because i said so

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4 years ago
The half-life of iodine-131 is 8 days. Chan Hee examines two samples of iodine-131. Sample 1: 10 g Sample 2: 20 g What can Chan
Illusion [34]
Chan Hee can expect to observe about the samples after 16 days is that three-fourths of each sample will have undergone radioactive decay. The best answer is letter B.
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4 years ago
Consider a metal single crystal oriented such that the normal to the slip plane and slip direction are at angles of 60° and 35°,
Vedmedyk [2.9K]

Answer:

19.5324 MPa

Explanation:

Information provided

Angle between the normal to the slip plane with tensile axis, \alpha=60^{o}


Angle by slip direction with tensile axis, \beta=35^{o}

Critical resolved shear stress, \tau_{c}=8 MPa

Applied stress \sigma=12 MPa

Shear stress at slip plane

\tau=\sigma cos\alpha cos\beta

\tau=12cos60^{o}cos35^{o}=4.915 MPa

\tau hence crystal won’t yield

Applied stress, \sigma for crystal to yield is given by

\sigma=\frac {\tau_{c}}{cos\alpha cos\beta}

\sigma=\frac {8}{cos60cos35}=19.53239342 MPa

\sigma=19.5324 MPa


7 0
3 years ago
A car with a mass of 1,500 kg requires a centripetal force of 640 N to safely follow a circular curve in the road at 13.4 m/s. W
Tamiku [17]
<h2>Answer</h2>

Radius is 421 m.

<u>Explanation </u>

A car with a mass of 1,500 kg requires a centripetal force of 640 N to safely follow a circular curve in the road at 13.4 m/s. Therefore, for radius we use formula which is Fc = mv ^ 2 / r,

As mass = m = 1500kg,

Centripetal force = Fc = 640N,

Velocity = v = 13.4 m / s

By putting values, Fc = mv ^ 2 / r,

r = mv ^ 2 / Fc,

=> r = ( 1500kg ) . ( 13.4 m / s) ^ 2 / 640,

=> r = ( 1500kg ) . ( 179.56 ) / 640,

r = 269340 / 640,

=> r = 420.84 m.

Radius is 421 m.

8 0
3 years ago
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The believe the answer to this is B
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