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tangare [24]
3 years ago
14

Identify the reagents necessary to achieve each of the following transformations: Na2Cr2O7, H2SO4, H2O EtOH, H+ H2O Fe2+, NaOH N

a2Cr2O7, H2SO4, H2O PCC, CH2Cl2 H2O, H+ Fe2+, H+ 1) R2B-H 2) H2O2, NaOH H2SO4, H2O, HgSO4 1) Br2 2) KOH H2SO4, H2O 1) R2B-H 2) H2O2, NaOH H2SO4, H2O, HgSO4 H2SO4, H2O 1) Br2, KOH 2) H2O, H+ 1) O3 2) DMS 1) O2 2) DMS 1) Br2 2) KOH K2Cr2O7, H2SO4, H2O
Chemistry
1 answer:
Gala2k [10]3 years ago
8 0
There’s not an answer in there.
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What is molar concept​
andrew11 [14]

Answer:

The molar mass of a substance is defined as the mass in grams of 1 mole of that substance. One mole of isotopically pure carbon-12 has a mass of 12 g. ... That is, the molar mass of a substance is the mass (in grams per mole) of 6.022 × 1023 atoms, molecules, or formula units of that substance.

Explanation:

8 0
3 years ago
A compound of a transition metal and iodine is 56.7% metal by mass.How many grams of the metal can be obtained from 630 g of thi
erma4kov [3.2K]

Answer:

357 g of the transition metal are present in 630 grams of the compound of the transition metal and iodine

Explanation:

In any sample of the compound, the percentage by mass of the transition metal is 56.7%. This means that for a 100 g sample of the compound, 56.7 g is the metal while the remaining mass, 43.3 g is iodine.

Given mass of sample compound = 630 g

Calculating the mass of iodine present involves multiplying the percentage by mass composition of the metal by the mass of the given sample;

56.7 % = 56.7/100 = 0.567

Mass of transition metal = 0.567 * 630 = 357.21 g

Therefore, the mass of the transition metal  present in 630 g of the compound is approximately 357 g

4 0
3 years ago
Which is a chemical property of iron
Artemon [7]

Answer:

The answer you have selected in the screenshot is correct.

Its tendency to react with oxygen is correct.

Hope this helps.

7 0
2 years ago
Write the chemical formula for the anion present in the aqueous solution of cuso4.
ki77a [65]
SO4 -2, or Sulfate

Hope this helps! :)
6 0
3 years ago
Read 2 more answers
I need help with this anyone?
valkas [14]
Just look it up on goog^le or a chart
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3 years ago
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