Answer:
The work done by the force is 6μJ
Explanation:
Suppose, A 30 nC charge is moved from a point where V₁ = 130 V to a point where V₂ = -70 V.
We need to calculate the work done by the force
Using formula of work done
Where, q = charge
=potential difference
Put the value into the formula
Hence, The work done by the force is 6μJ.
Answer:
by ideal gas pressure = 15529.475 kPa
by compressibility chart pressure = 12576 kPa
by steam tables Pressure = 12517 kPa
Explanation:
given data
temperature T = 400°C = 673 K
volume v = 0.02 m³/kg
to find out
pressure by ideal gas, compressibility chart and steam tables
solution
we know here by table
gas constant R is 0.4615 kJ/ kg-K
and critical temp Tc = 647.1 K
and critical pressure Pc = 22064 kPa
so by ideal gas pressure is
pressure = R×T / v
pressure = 0.4615 × 673 / 0.02
pressure = 15529.475 kPa
and
by compressibility chart
temperature reduce is = T/ Tc
temperature reduce Tr = 673 / 647.1
Tr = 1.040 K
so pseudo reduce volume is here
reduce volume Vr = v / ( RTc/Pc)
reduce volume Vr =
0.02 / ( 461.5(647.1) / 22064×10³)
reduce volume = 1.48
and we know by compressibility chart
reduce pressure Pr is 0.57
so
pressure = Pr × Pc
pressure = 0.57 × 22064 × 10³
pressure = 12576 kPa
and
from steam table
pressure is 12.5 MPa at 673 K and 0.020030 m³/kg
pressure is 15 MPa at 673 K and 0.015671 m³/kg
so
pressure P is
=
so
Pressure = 12517 kPa
Answer:
2.67kg
Explanation:
The maximum velocity, of a body experiencing simple harmonic motion is given by equation (1);
where is the angular velocity and A is the amplitude.
The problem describes the oscillation of a loaded spring, and for a loaded spring the angular velocity is given by equation (2);
where k is the force constant of the spring and m is the loaded mass.
We can make the subject of formula in equation (1) as follows;
We then combine equations (2) and (3) as follows;
According to the problem, the following are given;
We then substitute these values into equation (4) and solve for the unknown mass m as follows;
Squaring both sides, we obtain the following;