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OlgaM077 [116]
3 years ago
13

Calculate the [OH], [H30] and pOH given the following:

Chemistry
1 answer:
Kipish [7]3 years ago
4 0

Answer:

[H_3O^+]=2.40x10^{-13}M

[OH^-]=0.0417M

pOH=1.38

Explanation:

Hello,

In this case, we are able to compute the concentration of hydroxyl and hydronium by using both he pH and the pOH as shown below:

[OH^-]=10^{-pOH}

[H_3O^+]=10^{-pH}

Moreover, we are able to compute the pOH by:

pH+pOH=14\\pOH=14-pH=14-12.62=1.38

So we compute the concentrations:

[OH^-]=10^{-1.38}=0.0417M

[H_3O^+]=10^{-12.62}=2.40x10^{-13}M

Best regards.

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Hello!

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