Moles of KClO₃ = 59.3 / (39 + 35.5 + 16 x 3)
Moles of KClO₃ = 0.48
Molar ratio of KClO₃ to O₂ = 2 : 3
Moles of O₂ produced = 1.5 x 0.48
= 0.72
Mass of O₂ = moles x Mr
= 0.72 x 32
= 23.04 grams
1) Equlibrium reaction
CH3COOH (aq) = CH3COO(-) (aq) + H(+) (aq)
2) Equilibrium constant
Keq = Ka = [CH3COO-] [H+] / [CH3COOH]
3) Equilibrium concentrations
CH3COOH CH3COO- H+
start 1.40 0 0
react x 0 0
produced 0 x x
equilibrium 1.40 - x x x
=> Ka = x * x / (1.40 - x)
Approximation: given that Ka is very small x <<< 1,40 and 1.40 - x ≈ 1.40
=> Ka ≈ x^2 / 1.40
=> x^2 ≈ 1.40Ka = 1.40 * 1.8 * 10^ - 5 = 2.52 * 10^-5
=> x ≈ √(2.52 * 10^-5) ≈ 5.02 * 10^ -3 M
4) pH = log 1 / [H+]
[H+] = x = 5.02 * 10^-3M
=> pH ≈ log (1 / 5.02 * 10^-3) ≈ 2.3
Answer: 2.3
In this solution the solvent is water and the solutes are sugar, artificial flavor and artificial color. Another interesting property of solutions is that different concentrations of solute can be made. As all of you are aware, you can make very sweet Kool Aid and less sweet Kool Aid.
The cyanide is

A carbon atom has 4 valance electrons and nitrogen has 5. Below is a Lewis-dot-structure of cyanide.
:N≡C.
The carbon atom is still one electron short of having a full octet and so it will seize another electron from almost anything, making the cyanide ion negative and whatever it took the electron from it now positive.
the answer is not finding affordable housing, so that guy was wrong. Just a heads up