some regions of a polypeptide may coil or fold back on themselves. this is called <u>secondary structure</u> , and the coils or folds are held in place by <u>hydrogen bonds</u>
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After translation, primary structure is just the arrangement of amino acids. The interactions between the carbonyl, amino, and side groups of the amino acid polymer backbone inside the chain result in the secondary structure of proteins. These interactions are primarily fueled by hydrogen bonds, which result in the formation of alpha helices and beta sheets, which are the primary features of proteins' secondary structures.
To create a useful three-dimensional structure, tertiary structure requires more interactions within the protein chain. Disulfide bonds between cysteines, hydrophobic contacts, ionic bonding, and dipole-dipole interactions are a few of these interactions. To create a useful, three-dimensional protein structure, several protein chains interact in quaternary structure.
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Answer : We can produce 125.7 g of
.
Explanation : The reaction will be

The molecular mass of
is 64.1 g/mol
and molecular mass of
is 34.1 g/mol
For every mole of
we would need twice of
moles, so for every 3 moles of
we need 16 moles of 
Now, we can calculate number of moles
2.61 X (3/16) = 0.49 moles
Here, the molecular mass of
is 256.8 g
multiplying it with the number of 0.49 moles we get, 256.8 X 0.49 = 125.7 g of
.
Hence, 125.7 g of
will be produced.
This is thermodynamics. When you increase the temperature of an object, the particles gain on kinethic energy ergo the move faster. When you decrease it, they slow down.
A. Nonmetallic
B. Nonmetallic
C. Metallic
D. Nonmetallic
E. Metallic
Answer:
0.51M
Explanation:
Given parameters:
Initial volume of NaBr = 340mL
Initial molarity = 1.5M
Final volume = 1000mL
Unknown:
Final molarity = ?
Solution;
This is a dilution problem whereas the concentration of a compound changes from one to another.
In this kind of problem, we must establish that the number of moles still remains the same.
number of moles initially before diluting = number of moles after dilution
Number of moles = Molarity x volume
Let us find the number of moles;
Number of moles = initial volume x initial molarity
Convert mL to dm³;
1000mL = 1dm³
340mL gives
= 0.34dm³
Number of moles = initial volume x initial molarity = 0.34 x 1.5 = 0.51moles
Now to find the new molarity/concentration;
Final molarity =
=
= 0.51M
We can see a massive drop in molarity this is due to dilution of the initial concentration.