The ratio of the frequency at which he picks blue is 18:32 which simplifies to 9:16 but if you want a percentage its 36%
ANSWER
The domain of the function is
or
[-3,6]
EXPLANATION
The domain of a function refers to the values of x for which the function is defined.
From the graph, we can see that the function begins at (-3,6) and ends at (6,-4).
Therefore the function is defined for x=-3 to x=6.
Hence the domain of the function is
or
[-3,6]
Answer:
3/5
Step-by-step explanation:
30 + 40 + 15 + 15 = 100
40/100 will be green
100/100 - 40/100 = 60/100
60/100 will NOT be green
60 ÷ 5 = 12
100 ÷ 5 = 20
12 ÷ 4 = 3
20 ÷ 4 = 5
3/5
<h3><u>The value of x is equal to 1.</u></h3><h3><u>6(x + 2) = 20x - 2</u></h3>
<em><u>Distributive property.</u></em>
6x + 12 = 20x - 2
<em><u>Add 2 to both sides.</u></em>
6x + 14 = 20x
<em><u>Subtract 16x from both sides.</u></em>
14 = 14x
<em><u>Divide both sides by x.</u></em>
x = 1
Answer:
- P(≥1 working) = 0.9936
- She raises her odds of completing the exam without failure by a factor of 13.5, from 11.5 : 1 to 155.25 : 1.
Step-by-step explanation:
1. Assuming the failure is in the calculator, not the operator, and the failures are independent, the probability of finishing with at least one working calculator is the complement of the probability that both will fail. That is ...
... P(≥1 working) = 1 - P(both fail) = 1 - P(fail)² = 1 - (1 - 0.92)² = 0.9936
2. The odds in favor of finishing an exam starting with only one calculator are 0.92 : 0.08 = 11.5 : 1.
If two calculators are brought to the exam, the odds in favor of at least one working calculator are 0.9936 : 0.0064 = 155.25 : 1.
This odds ratio is 155.25/11.5 = 13.5 times as good as the odds with only one calculator.
_____
My assessment is that there is significant gain from bringing a backup. (Personally, I might investigate why the probability of failure is so high. I have not had such bad luck with calculators, which makes me wonder if operator error is involved.)
