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Black_prince [1.1K]
3 years ago
11

I NEEED HELP PLEASE! :)

Chemistry
2 answers:
lesantik [10]3 years ago
5 0

Answer:

okay I do t know if I ×+÷_ but I think the answer is 348

Sindrei [870]3 years ago
3 0

Answer:

66.67%

Explanation:

Percent yield basically says what percent of theoretical yield (yield that you expect to get) did you produce in actual reality. So theoretically you were supposed to make 24 cupcakes but actually you made 16 cupcakes so

Percent yield = actual yield/theoretical yield *100%

                     = 16/24 * 100%

                     = 66.67% was your percent yield of cupcakes

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What did Rutherford’s scattering experiment reveal about the structure of atoms?
Stels [109]

Answer:

C

Explanation:

This experiment by Rutherford involved the firing of alpha particles at gold foils. It is also. called the gold foil experiment.

He fired these alpha particles at different points. He noticed that at some points, there were deflections, while at some other points, there were no deflections. It is necessary to state that these alpha particles are positively charged. For there to be a deflection, there must have been a kind of repulsion between the gold foil and the alpha particles.

From the basic physics of like repels like, he knew for sure that there must be dense positive core in the atom that is causing the deflection of the alpha particles. This enabled him to come up with the theory that the atom contained a small dense positive core called the nucleus

7 0
4 years ago
How many moles are in 36.0g of H20
Nadusha1986 [10]

Answer:

The answer to your question is 2 moles

Explanation:

Data

mass of H₂O = 36 g

moles of H₂O = ?

Process

1.- Calculate the molar mass of water (H₂O)

H₂O = (1 x 2) + (16 x 1) = 2 + 16 = 18 g

2.- Use proportions and cross multiplication to find the answer.

               18 g of H₂O ---------------- 1 mol

               36 g of H₂O --------------- x

                     x = (36 x 1) / 18

                     x = 36/18

                     x = 2 moles

4 0
4 years ago
Read 2 more answers
Classify this statement as always true, AT; sometimes true, ST; or never true, NT. To obtain a value for the number of moles usi
ozzi
AT, STP in chemistry is the abbreviation for Standard Temperature and Pressure. STP most commonly is used when performing calculations on gases, such as gas density
8 0
4 years ago
Sodium carbonate (na2co3) is used to neutralize the sulfuric acid spill. how many kilograms of sodium carbonate must be added to
jenyasd209 [6]
<span>5.45 x 10^3 kg of sodium carbonate is needed to neutralize 5.04 kg of sulfuric acid. For this, I will assume you have pure H2SO4. So first, you need to calculate the molar mass of H2SO4 and Na2CO3. Lookup the atomic weights of all the elements involved. Atomic weight of Sodium = 22.989769 Atomic weight of Sulfur = 32.065 Atomic weight of Carbon = 12.0107 Atomic weight of Oxygen = 15.999 Atomic weight of Hydrogen = 1.00794 Molar mass of H2SO4 = 2 * 1.00794 + 32.065 + 4 * 15.999 = 98.07688 g/mol Molar mass of Na2CO3 = 2 * 22.989769 + 12.0107 + 3 * 15.999 = 105.987238 g/mol The balanced equation for the reaction of Na2CO3 with H2SO4 is Na2CO3 + H2SO4 => Na2SO4 + CO2 + H2O so for every mole of sulfuric acid to be neutralized, you need 1 mole of sodium carbonate. You can determine the number of moles of sulfuric acid you have and then calculate the mass of that many moles of sodium carbonate. But, there's an easier way. Just use the relative mass differences between sodium carbonate and sulfuric acid. So 105.987238 g/mol / 98.07688 g/mol = 1.080655 So that means for every kg of sulfuric acid, you need 1.080655 kg of sodium carbonate. Now do the multiplication. 5.04 x 10^3 kg * 1.080655 = 5.4465 x 10^3 kg. Since you only have 3 significant figures for your data, round the result to 3 significant figures, giving 5.45 x 10^3 kg</span>
3 0
3 years ago
The half-life of gold-198 is 2.7 days. After
Pie

Answer: 8.1 days

Explanation:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant

t = age of sample

a = let initial amount of the reactant = x

a - x = amount left after decay process= \frac{x}{4} 

a) to find rate constant

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

t_{\frac{1}{2}}=\frac{0.693}{k}

k=\frac{0.693}{2.7days}=0.257days^{-1}

b) for completion of one fourth of reaction

t=\frac{2.303}{k}\log\frac{x}{\frac{x}{4}}

t=\frac{2.303}{0.257}\log{4}

t=8.1days

Thus after 8.1 days , one fourth of original amount will remain.

8 0
4 years ago
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