Answer:38.66 m
Explanation:
Given
launch angle 
launch velocity 
center of mass continue to travel its original Path so it center of mass will be at a distance of



Center of mass will be at 
(b)if one of the piece will be at x=26 m then other will be at




Answer:
the total momentum is 8 .2 kg m/s in north direction.
Explanation:
given,
mass(m₁) 3.00 kg, moving north at v₁ = 3.00 m/s
mass(m₂) 4.00 kg, moving south at v₂ = 3.70 m/s
mass(m₃) 7.00 kg, moving north at v₃ = 2.00 m/s
north as the positive axis
south as the negative axis
now
total momentum = m₁v₁ + m₂ v₂ + m₃ v₃
total momentum = 3 x 3 - 4 x 3.7 + 7 x 2
= 9 - 14.8 + 14
= 8 .2 kg m/s
hence, the total momentum is 8 .2 kg m/s in north direction.
Answer:
first object final velocity =2m/s
second = 12m/s
Explanation:
i hope this will help you,..,
Answer:
S = 122.5m
Explanation:
Given the following data;
Acceleration due to gravity = 9.8m/s²
Time, t = 5 seconds
Since it's a free fall, initial velocity, u = 0
To find the displacement, we would use the second equation of motion given by the formula;

Where;
- S represents the displacement or height measured in meters.
- u represents the initial velocity measured in meters per seconds.
- t represents the time measured in seconds.
- a represents acceleration measured in meters per seconds square.
Substituting into the equation, we have;

S = 122.5m.
The tree might get swept away by the current and it will disappear when it catches on something