Answer:
= 0.014 g of BaCO3
Explanation:
Let x = mol/L of BaCO3 that dissolve.
This will give;
x mol/L Ba2+ and x mol/L CO32-
But;
Ksp = 5.1x10^-9.
Therefore;
Ksp = 5.1 x 10^-9 = (x)(x)
Thus;
x = molar solubility
= √ (5.1 x 10^-9)
= 7.1 x 10^-5 M
Therefore;
Mass BaCO3 = 7.1 x 10^-5 M x 1 L x 197.34 g/mol
= 0.014 g
Answer:
E = energy = ? ,
λ = Wavelength = 5.89 × 10^-7 m —> = 589 ×10 ^-9 m ,
h =Planck constant = 6.63 × 10^-34 J.s ,
f = frequency of photo/ electromagnetic radiation = c/λ ,
c = Speed of light in a vacuum = 3 × 10^8 m/s
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I hope I helped you^_^
Answer : The photon energy of this light in units of nanometers, (nm) is,
Solution :
Formula used :
where,
E = energy of photon =
h = Planck's constant =
c = speed of light =
= wavelength = ?
Now put all the given values in the above formula, we get:
conversion used :
Therefore, the photon energy of this light in units of nanometers, (nm) is,
Answer: Sorry, I do not understand.
Indique dos diferencias entre la filtración por gravedad y la filtración al vacío.
?