The resultant force on the animal = Resultant mass * total acceleration
F = 0.2 * 2.5 to the right
F = 0.5 to the right.
As, girl exerting a force of 3.5 N & it's not mentioned that she is in right or left, so the force exerting by boy would be either:
3.5-0.5 = 3 OR 3.5+0.5 = 4
If boy exerting a greater force then, answer will be 4 N & if girl exerting a greater force the, answer will be 3 N
Hope this helps!
Answer:
N₂= 697.24 m/s,
O₂= 652.38 m/s
CO₂= 393.35 m/s
Explanation:
The rms speed, of a gas is the following:
<em>where R: is the ideal gas constant, T: is the temperature and M: is the molar mass. </em>
<u>Knowing that the molar mass of the given gases are:</u>
N₂ = 14.0067 g/mol = 14.0067x10⁻³ kg/mol
O₂ = 15.999 g/mol = 15.999x10⁻³ kg/mol
CO₂ = 44.009 g/mol = 44.009x10⁻³ kg/mol
Also that T is 0 °C = 273 K, and R = 8.314 J/ K.mol = 8.314 kg.m². s⁻². K⁻¹. mol⁻¹. The rms speed of the gases are:
For N₂:
For O₂:
For CO₂:
Therefore, the rms speed of N₂ is 697.24 m/s, of O₂ is 652.38 m/s and of CO₂ is 393.35 m/s
I hope it helps you!
Answer:
a) initial position = 10m
b) average velocity = 30m/s
Explanation:
The general equation of a motion with constant velocity is given by:
(1)
So: initial position
v: average velocity
t: time
You have the following equation:
(2)
If you compare the equations (1) and (2) you obtain that:
hence:
a) initial position = 10m
b) average velocity = 30m/s
Answer:
T'=92.70°C
Explanation:
To find the temperature of the gas you use the equation for ideal gases:
V: volume = 3000cm^3 = 3L
P: pressure = 1250mmHg; 1 mmHg = 0.001315 atm
n: number of moles
R: ideal gas constant = 0.082 atm.L/mol.K
T: temperature = 27°C = 300.15K
For the given values you firs calculate the number n of moles:
this values of moles must conserve when the other parameter change. Hence, you have V'=2L and P'=3atm. The new temperature is given by:
hence, T'=92.70°C