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olya-2409 [2.1K]
3 years ago
14

Las temperaturas de fusión y ebullición del agua utilizadas en las escalas de temperatura son valores que es importante indicar

el valor que corresponden a una presión de 1atm. ¿Por qué crees que es importante indicar el valor de la presión?
Physics
1 answer:
antoniya [11.8K]3 years ago
7 0

Answer:

Suppose that you have water in a metallic bowl.

Now, you start heating the water until it reaches the boiling point.

At this point the water starts transitioning from liquid phse to gas phase, now, you need to think this as the kinetic energy of the water increases to the point where it is stronger than the pressure and it can "escape" the liquid mass.

Then, if we increase the pressure, the temperature needded to escape (to change of phase) also needs to increase.

A more "thermodinamical" way to explain it, is that we can define a curve P(T) of transitions, and we also can define a curve T(P) (the inverse)

So for different values of Pressure, we should see different values of temperature for the changes of phase.

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Read 2 more answers
A sample of n2 gas occupies a volume of 746 ml at stp. What volume would n2 gas occupy at 155 ◦c at a pressure of 368 torr?
musickatia [10]

Answer:

2.41 L

Explanation:

We can solve the problem by using the ideal gas equation, which can be rewritten as:

\frac{p_1 V_1}{T_1}=\frac{p_2 V_2}{T_2}

where we have:

p_1 = 1.01\cdot 10^5 Pa (initial pressure is stp pressure)

V_1 = 746 mL = 0.746 L = 7.46\cdot 10^{-4}m^3 is the initial volume

T_1 = 0^{\circ}=273 K is the initial temperature (stp temperature)

p_2 = 368 torr = 4.9\cdot 10^4 Pa is the final pressure

V_2 = ? is the final volume

T=155^{\circ}=428 K is the final temperature

By substituting the numbers inside the formula and solving for V2, we find the final volume:

V_2 = \frac{p_1 V_1 T_2}{T_1 p_2}=\frac{(1.01\cdot 10^5 Pa)(7.46\cdot 10^{-4} m^3)(428 K)}{(273 K)(4.9\cdot 10^4 Pa)}=2.41\cdot 10^{-3} m^3

which corresponds to 2.41 L.

7 0
4 years ago
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