2. Which pair of elements would have the greatest difference in electronegativities? *

lesya692 [45]

Answer:

I'm sorry to say but there is no statements in this question meaning no one will be able to answer them with out them.. what are the statements?

Explanation:

4 0

3 years ago

Glucose is a product of photosynthesis. where do the carbon atoms in glucose come from?

sineoko [7]

Carbon atoms in glucose come from carbon dioxide.

5 0

3 years ago

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It was calculated that 4.3mL of 0.417 M HCl is required to titrate 11.9 mL of 0.151 M Mg(OH)2. Show evidence 2 HCl(aq) + Mg(OH)2

Lapatulllka [165]

Answer:

See explanation.

Explanation:

Hello,

In this case, for the described chemical reaction:

2 HCl(aq) + Mg(OH)2(aq) → MgCl2(aq) + 2 H2O(l)

We can notice there is a 2:1 molar ratio between the moles of hydrochloric acid and magnesium hydroxide, therefore, at the equivalence point:

$n_{HCl}=2*n_{Mg(OH)_2}$

And in terms of volumes and concentrations we verify:

$V_{HCl}M_{HCl}=2*V_{Mg(OH)_2}M_{Mg(OH)_2}$

So we use the given data to proof it:

$4.3mL*0.417M=2*11.9mL*0.151M\\1.793=3.594$

Therefore, we can conclude the data is wrong by means of the 2:1 mole ratio that for sure was not taken into account. This is also supported by the fact that normalities are actually the same, but the nomality of magnesium hydroxide is the half of the hydrochloric acid normality since the acid is monoprotic and the base has two hydroxyl ions.

Best regards.

4 0

3 years ago

A solution contains 0.021 M Cl? and 0.017 M I?. A solution containing copper (I) ions is added to selectively precipitate one of

slavikrds [6]

Answer:

A precipitate will begin to form at [Cu+] = 3.0 *10^-10 M

The precipitate formed is CuI

Explanation:

Step 1: Data given

The solution contains 0.021 M Cl- and 0.017 M I-.

Ksp(CuCl) = 1.0 × 10-6

Ksp(CuI) = 5.1 × 10-12.

Step 2: Calculate [Cu+]

Ksp(CuCl) = [Cu+] [Cl-]

1.0 * 10^-6 = [Cu+] [Cl-]

1.0 * 10^-6 = [Cu+] [0.021]

[Cu+] = 1.0 * 10^-6 / 0.021

[Cu+] = 4.76 *10^-5 M

Ksp(CuI) = [Cu] [I]

5.1 * 10^-12 = [Cu+] [I-]

5.1 * 10^-12 =[Cu+] [0.017]

[Cu+] = 5.1 * 10^-12 / 0.017

[Cu+] = 3.0 *10^-10 M

[Cu+]from CuI hast the lowest concentration

A precipitate will begin to form at [Cu+] = 3.0 *10^-10 M

The precipitate formed is CuI

5 0

3 years ago

The Hope diamond has a mass of 44.0 carats and a density of 3.51 g/cm3. What is the volume of the Hope diamond? (Hint: 1 carat =

Georgia [21]

Q=44.0 ct
p=3.51 g/cm³
Δq=0.200 g/ct

m=q×Δq

v=m/p=q×Δq/p

v=44.0×0.200/3.51≈2.5 cm³

C. 2.5 cm³

7 0

3 years ago