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Pie
3 years ago
13

PLEASE HELP: 3.01x10^23 molecules of SO3 is how many moles? Please tell me how you got it thank you!

Chemistry
1 answer:
zysi [14]3 years ago
8 0
Divide 3.01x10^23 by the Avogadro's number <span>6.02x10^23

that is 

</span>3.01x10^23 / 6.02x10^23 = 0.5 mol of SO3
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What is buffers and mention its importance?
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Answer:

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Explanation:

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5 0
3 years ago
The concentration of a diluted "wine" sample was found to be 0.24 %(v/v) ethanol. Assuming the wine was diluted by 75x before an
Softa [21]

Answer:

The original concentration of ethanol was 18 % (v/v)

Explanation:

For the analysis of a sample, mostly dilutions are made of the original concentrated sample. The analysis results obtained from the diluted sample are then calculated for the concentrated samples.

According to the given data, the wine sample was diluted 75 times. This means that the initial concentration of ethanol was 75 times more than the final concentration i.e. 0.24 % (v/v). So mathematically:

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original concentration (v/v)= 0.24 % x 75

original concentration (v/v) = 18 %

3 0
3 years ago
64g of sulfur dioxide (SO2) contains 32g of oxygen. Calculate how much sulfur it contains?
KengaRu [80]
Mass of SO2 = mass of sulfur+ mass of oxygen
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⇒ mass of sulfur= 32 g.

There is 32 g of sulfur in 64 g of SO2~
6 0
3 years ago
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nevsk [136]
Transpiration i think
6 0
3 years ago
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Answer:

2.57 e-9

Explanation:

The formula is H3O=10^-Ph

10^-8.59=2.57 e-9

6 0
2 years ago
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