Answer:
Aquarius beginning in the mid-3rd millennium. The north and south celestial poles are the two imaginary points in the sky where the Earth's ... In about 5,500 years, the pole will have moved near the position of the star ... The south celestial pole is visible only from the Southern Hemisphere.
Explanation:
Use the chart to help you look carefully at the numbers and the volumes to figure the questions out hope this helps
Answer:
Three orbitals
Explanation:
The electronic configuration of carbon is given as follows;
1s²2s²2p²
Therefore, out of the six electrons of the carbon atoms, 4 fill the 1s and 2s orbitals with 2 electrons each, while the two remaining electrons are situated in the 2p orbital, with the electrons in the 2p orbital will remain unpaired such that they will have similar quantum numbers in accordance with Pauli exclusion principle.
Answer:
contain hereditary information
break down food into energy
Explanation:
Hereditary information is contained in genes and genes are found inside the cell. This implies that the cell contains hereditary information of organisms. This hereditary information is passed on during cell division from parent to daughter cells.
Metabolism occurs in the cells. The cells use oxygen to break down food materials to produce energy.
For the given molecule, we are asked to give-
- The electron configuration of an isolated B atom
- The electron configuration of an isolated F atom
- Hybrid orbitals should be constructed on the B atom to make the B–F bonds in Boron tri flouride
- valence orbitals, if any, remain unhybridized on the B atom.
- The electron configuration of an isolated B atom:
as atomic number of B is 5
electronic configuration will be [He] 2s² 2p¹
- The electron configuration of an isolated F atom:
as atomic number of F is 9
electronic configuration will be [He] 2s² 2p5
- Hybrid orbitals should be constructed on the B atom to make the B–F bonds in Boron tri flouride will be sp2.
as the one s and two of p orbital from the valance shell will hybridised to make 3 hybrid orbital of B resulting in 3 B-F bonds.
- valence orbitals, if any, remain unhybridized on the B atom will be 1
To know more about hybrisisation:
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