Answer:
The balanced equation of the reaction is given as follows:
M₂CO₃ + 2HCl ---> 2MCl + H₂O + CO₂
The mole ratio of the metallic carbonate to carbon (iv) oxide is 1:1
The metal is Lithium
Explanation:
The balanced equation of the reaction is given below:
M₂CO₃ + 2HCl ---> 2MCl + H₂O + CO₂
From the equation of reaction, 1 ,mole of the metal carbonate reacts with 2 moles of excess HCl to produce 2 moles of the metallic salt, 1 mole of water and 1 mole of CO₂.
The mole ratio of the metallic carbonate to carbon (iv) oxide is 1:1
Molar mass of CO₂ = 44 g/mol
Number of moles of CO₂ in 1.206 g of CO₂ = 1.206 g / 44 g/mol = 0.0274 moles
Therefore, 2.002 g of M₂CO₃ = 0.0274 moles since all the metallic carbonate was reacted with excess HCl
mass of 1 mole of M₂CO₃ = 2.002/0.0274 = 73.06 g
M₂CO₃ =73.06
2 * M + 12 + 3 *16 = 73.06
2M = 73.06 - 60
M = 13.06/2
M = 6.53 g
Since, the metal belongs to group 1, the metal is most likely Lithium as the molar mass of M is closest to Lithium.
