The equilibrium constant for this reaction at 350°C is determined as 5.85.
<h3>Concentration of each component</h3>
concentration of bromine, C(Br) = 0.6 mol/1 = 0.6
concentration of iodine, C(I) = 1.6 mol/1 = 1.6
<h3>Create an ICE table</h3><h3>What is ICE table?</h3>
An ICE table is a tabular system of keeping track of changing concentrations in an equilibrium reaction.
ICE is an abbreviation that stands for initial, change, equilibrium.
Create ICE table for the reactants and products formed;
Br2(g) + I2(g) ↔ 2IBr(g)
I 0.6 1.6 0
C -1.19 -1.19 1.19
E 0.6 - 1.19 1.6 - 1.19 1.19
E = -0.59 0.41 1.19
<h3>Equilibrium constant </h3>
The equilibrium constant is calculated as follows;
KC = [IBr]²/[Br][I]
KC = (1.19²) / (0.59 x 0.41)
KC = 5.85
Thus, the equilibrium constant for this reaction at 350°C is determined as 5.85.
Learn more about equilibrium constant here: brainly.com/question/19340344
#SPJ1
e. ice changed to gas
f.the specific heat of vaporisation is greater than heat of fusion because eventually all the ice changed to gas it becomes vaporisation
Water!!! (H2O) ........... :)
Answer:
2,799.7598
Explanation:
If you like my answer than please mark me brainliest thanks
When 1 mole of Zn and 2 mole of O₂ reacts togethor, It will produce 1 mole of ZnO as O₂ is excess reagent and Zn will act as Limiting reagent and thus it limits the amount of product formed.
<h3>What is Limiting reagent ?</h3>
Limiting reagents are the substances that are completely consumed first in a chemical reaction.
Given ;
- Amopunt of Zn : 1 mole
- Amount of O₂ : 2 mole
Given equation ;
2Zn + O₂ --> 2ZnO
As according to given chemical equation,
2 moles Zn of reacts with 1 mole of O₂ to produce 2 moles of ZnO.
Therefore,
1 mole of Zn will require 0.5 mole of O₂.
But,
the given amount of O₂ is 2 mole which is excess
Hence,
Zn here will act as the Limiting reagent, According to which the amount of product formed will be decided.
Therefore,
If 2 mole Zn produces : 2 moles of ZnO (According to given balanced equation)
Thus,
1 mole of Zn will produce = 2/2 x 1
= 1 mole of ZnO
Hence, When 1 mole of Zn and 2 mole of O₂ reacts togethor, It will produce 1 mole of ZnO as O₂ is excess reagent and Zn will act as Limiting reagent and thus it limits the amount of product formed.
Learn more about Limiting reagent here ;
brainly.com/question/11848702
#SPJ1
