Is halved. A 6Ω resistor connected to a voltage source which voltage is decreased from 12V to 6V the current passing through the resistor is halved.
The key to solve this problem is applying Ohm's Law V = R I, clearing I from the equation, we obtain I = V/R. Then, the current is directly proportional to the voltage and inversely proportional to the resistance.
V = 12V and R = 6Ω
I = 12V/6Ω = 2A
V = 6V and R = 6Ω
V = 6V/6Ω = 1A
As we can see the current is halved if the voltage descreased from 12V to 6V
Answer:
Explanation:
The force of attraction between 2 masses.
Answer:
a. push
Explanation:
Voltage is the force or pressure that is responsible for pushing the charge or electrons to flow in a closed-looped electrical circuit. This flow of electrons (charge) is called the electric current. It is also defined as the difference in electric potential per unit charge between two points in an electric field.
Answer:
diameter of transmission is 3.473 mm
Explanation:
given data
current = 300 A
total wire length = 1.0 m
voltage drop = 0.55 V
solution
as here Resistivity of copper is = 1.68 × 
ohm- m
so we get here resistance of wire that is
resistance = 
..............1
R = 
R = 1.774 × 
ohm
and now we get diameter of wire that is
R = 
.............2
d² = 
...............3
put here value
d² = 
d = 
d = 3.473 × m
d = 3.473 mm
so diameter of transmission is 3.473 mm
