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3 years ago

A body of mass m moves along y such that at time t its position is y(t)= at^2 – bt + c, where a, b, c are constant.

Physics

1 answer:

Akimi4 [234]3 years ago

3 0

Answer:

what do u need help with

Explanation:

A body of mass m moves along X-axis such that its position co-ordiante at any instant t is x = `at^(4)

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Which of the following best describes the role of attention from a caregiver on the development of intelligence?

WINSTONCH [101]

A child's IQ may increase with attention from a caregiver" is the one among the following that best describes the role of attention from a caregiver on the development of intelligence. The correct option among all the options that are given in the question is the first option. I hope the answer has helped you.

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3 years ago

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An Ethernet cable is 4.15 m long. The cable has a mass of 0.210 kg. A transverse pulse is produced by plucking one end of the ta

kobusy [5.1K]

Answer:

95.3 N

Explanation:

The tension in the cable is found by the equation:

$T=\mu v^2$

Where $\mu$ is the mass density, and $v$ is velocity.

First we find mass density:

$\mu =\frac{m}{L}$ --> $m$ is mass: $m=0.21kg$ and $L$ is length of the cable: $L=4.15m$ , so:

$\mu=\frac{0.21kg}{4.15m} =0.0506kg/m$

And the velocity:

$v=\frac{distance}{time} =\frac{d}{t}$

the time is $t=0.765s$ and in that time the pulse went down and back along the cable 4 times, if one time down and back is:

2*4.15m=8.3m,

four times this path is:

4*8.3m=33.2m

thus, the velocity is:

$v=\frac{distance}{time} =\frac{33.2m}{0.765s}=43.4m/s$

And with this data we can now calculate the tension:

$T=(0.0506kg/m)(43.4m/s)^2\\T=95.3N$

The tension is 95.3N

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3 years ago

Light of wavelength 656 nm and 410 nm emitted from a hot gas of hydrogen atoms strikes a grating with 5300 lines per centimeter.

padilas [110]

Answer:

$20.32^{\circ}$ and $44.08^{\circ}$

$12.56^{\circ}$ and $25.77^{\circ}$

Explanation:

$\lambda$ = Wavelength

$\theta$ = Angle

m = Order

Distance between grating is given by

$d=\dfrac{1}{5300}\\\Rightarrow d=0.0001886\ \text{cm}$

$\lambda=656\ \text{nm}$

We have the relation

$d\sin\theta=m\lambda\\\Rightarrow \theta=\sin^{-1}\dfrac{m\lambda}{d}$

m = 1

$\theta=\sin^{-1}\dfrac{1\times 656\times 10^{-9}}{0.0001886\times 10^{-2}}\\\Rightarrow \theta=20.35^{\circ}$

m = 2

$\theta=\sin^{-1}\dfrac{2\times 656\times 10^{-9}}{0.0001886\times 10^{-2}}\\\Rightarrow \theta=44.08^{\circ}$

The first and second order angular deflection is $20.32^{\circ}$ and $44.08^{\circ}$

$\lambda=410\ \text{nm}$

m = 1

$\theta=\sin^{-1}\dfrac{1\times 410\times 10^{-9}}{0.0001886\times 10^{-2}}\\\Rightarrow \theta=12.56^{\circ}$

m = 2

$\theta=\sin^{-1}\dfrac{2\times 410\times 10^{-9}}{0.0001886\times 10^{-2}}\\\Rightarrow \theta=25.77^{\circ}$

The first and second order angular deflection is $12.56^{\circ}$ and $25.77^{\circ}$ .

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3 years ago

A mass of 10.0 kg is in a gravitational field of 3.50 N/kg. What force acts on the mass?

mash [69]

Answer:

Force=35 N

Explanation:

Given data

mass m=10.0 kg

Gravitational field E=3.50 N/kg

To find

Force

Solution

From definition of gravitational field intensity.

$E_{gravitational-field }=\frac{Force}{mass}\\ E=F/m\\F=mE\\F=(10.0 kg)*(3.50 N/kg)\\F=35N$

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Montano1993 [528]

40/5=8. His speed increases 8mph/second :)

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3 years ago

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