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rosijanka [135]
3 years ago
10

Carbon dioxide used as a natural refrigerant flows through a cooler at 10 MPa, which is supercritical, so no condensation occurs

. The inlet is at 220°C and the exit is at 50°C. Find the specific heat transfer.

Engineering
2 answers:
kupik [55]3 years ago
5 0

Answer:

The answer which is a calculation can be found as an attached document

Explanation:

MrRa [10]3 years ago
4 0

Answer:

Answer is -286.78 kJ/kg

Refer below.

Explanation:

Refer to the pictures for brief explanation.

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1. Copy the file Pay.java (see Code Listing 1.1) from the Student CD or as directed by your instructor. 2. Open the file in your
Mrac [35]

Answer:

Code Listing 1.1 (Pay.java)

import java.util.Scanner; // Needed for the Scanner class

/**

This program calculates the user's gross pay.

*/

public class Pay

{

public static void main(String[] args)

{

// Create a Scanner object to read from the keyboard. Scanner keyboard = new Scanner(System.in);

// Identifier declarations

double hours; // Number of hours worked

double rate; // Hourly pay rate double pay; // Gross pay

// Display prompts and get input. System.out.print("How many hours did you work? "); hours = keyboard.nextDouble();

System.out.print("How much are you paid per hour? ");

rate = keyboard.nextDouble();

// Perform the calculations. if(hours <= 40)

pay = hours * rate;

else

pay = (hours - 40) * (1.5 * rate) + 40 * rate;

// Display results. System.out.println("You earned $" + pay);

}

}

Code Listing 1.2 (SalesTax.java)

import java.util.Scanner; // Needed for the Scanner class

/**

This program calculates the total price which includes

sales tax.

*/

public class SalesTax

{

public static void main(String[] args)

{

// Identifier declarations final double TAX_RATE = 0.055; double price;

double tax

double total; String item;

// Create a Scanner object to read from the keyboard. Scanner keyboard = new Scanner(System.in);

// Display prompts and get input. System.out.print("Item description: "); item = keyboard.nextLine(); System.out.print("Item price: $");

price = keyboard.nextDouble();

// Perform the calculations. tax = price + TAX_RATE;

totl = price * tax;

// Display the results. System.out.print(item + "  $"); System.out.println(price); System.out.print("Tax $"); System.out.println(tax); System.out.print("Total $"); System.out.println(total);

}

}

5 0
4 years ago
What are the units or dimensions of the shear rate dv/dy (English units)? Then, what are the dimensions of the shear stress τ= μ
swat32

Answer:

1) Dimensions of shear rate is [T^{-1}] .

2)Dimensions of shear stress are [ML^{-1}T^{-2}]

Explanation:

Since the dimensions of velocity 'v' are [LT^{-1}] and the dimensions of distance 'y'  are [L] , thus the dimensions of \frac{dv}{dy} become

\frac{[LT^{-1}]}{[L]}=[T^{-1}] and hence the units become s^{-1}.

Now we know that the dimensions of coefficient of dynamic viscosity \mu are [ML^{-1}T^{-1}] thus the dimensions of shear stress can be obtained from the given formula as

[\tau ]=[ML^{-1}T^{-1}]\times [T^{-1}]\\\\[\tau ]=[ML^{-1}T^{-2}]

Now we know that dimensions of momentum are [MLT^{-1}]

The dimensions of Area\times time are [L^{2}T]

Thus the dimensions of \frac{Moumentum}{Area\times time}=\frac{MLT^{-1}}{L^{2}T}=[MLT^{-2}]

Which is same as that of shear stress. Hence proved.

4 0
3 years ago
Engine horsepower decreases ________% for every___________feet above sea level.
Nitella [24]

Answer:

Engine horsepower decreases <u>3.5%</u> for every <u>1,000</u> feet above sea level.

4 0
3 years ago
Write a Nested While Loop that will increment the '*' from 1 to 10.
andrey2020 [161]

Answer:

The program is as follows:

i = 1

while(i<11):

   j = 1

   while(j<=i):

       print('*', end = '')

       j += 1

   i += 1

   print()

Explanation:

Initialize i to 1

i = 1

The outer loop is repeated as long as i is less than 11

while(i<11):

Initialize j to 1

   j = 1

The inner loop is repeated as long as j is less than or equal i

   while(j<=i):

This prints a *

       print('*', end = '')

This increments j and ends the inner loop

       j += 1

This increments i

   i += 1

This prints a blank and ends the inner loop

   print()

8 0
3 years ago
An incremental encoder is rotating at 15 rpm. On the wheel there are 40 holes. How many degrees of rotation would 1 pulse be?
elena-s [515]

Answer:

1 pulse rotate = 9 degree

Explanation:

given data

incremental encoder rotating = 15 rpm

wheel holes = 40

solution

we get here first 1 revolution time

as 15 revolution take = 60 second

so 1 revolution take = \frac{60}{15}

1 revolution take = 4 seconds

and

40 pulse are there for 1 revolution

40 pulse for 360 degree

so 1 pulse rotate is = \frac{360}{40}

1 pulse rotate = 9 degree

3 0
3 years ago
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