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UNO [17]
3 years ago
12

Balance the combustion reaction between octane and oxygen. 2C8H18 + O2 → CO2 + H2O

Chemistry
1 answer:
LiRa [457]3 years ago
7 0

Answer: 2C8H18 + 25O2 -> 16CO2 + 18H2O

Explanation:

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In the article "A Sea of Garbage" what message is each cartoon trying to convey to readers? Do they succeed?
sertanlavr [38]

Answer:

  1. yes in the article I see of garbage what's messages each carton trying to convey to your readers with a success obviously they do suck said they succeed because like that's really great day socks said is your garbage is like a pool of garbage work garbage are gathered together they are together a you get one talking about you know when cabbage and together they make efficient use of them okay I mean garbage garbage garbage garbage so I don't know I don't know I don't know I don't know I don't know but it's really is regret it regret it was someone couldn't wish for our young people pick them up and see if garbage and it's really not making sense cuz when you see a sea of garbage that means there's water in there and people pull up garbage in be like water pollution or something but I'm actually not really like sure but I have a slight idea of like what we talking about here right now and it's great
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3 years ago
Which is NOT a property of metals?
gladu [14]

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Silicon????

Explanation:

I searched your question and it gave me that. I hope it helps. If not sorry!

4 0
3 years ago
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How many neutrons make up one of these potassium atoms <br>​
julia-pushkina [17]

Answer:

4

Explanation:

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5 0
3 years ago
Natural atom of the same element may have the same _________?
Minchanka [31]

Answer:B

Explanation:

4 0
3 years ago
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A 48 kg sample of water absorbs 366 kJ of heat. the water was initially at 20.3 ∘C, what is its final temperature?
belka [17]

Answer:

The final temperature of water = 22.1224 °C

Explanation:

<u>Step 1</u> : defien the formula for heat transfer

q = m*c*ΔT

with q = heat transfer

with m = mass of the substance

with c = specific heat ( of water in this case)

with ΔT = difference between final temperature and initial temperature

In this case :

q=366kJ = 366 *10^3 J

mass of water = 48kg = 48000g

c= specific heat of wwater = 4.184 J / g °C

initial temperature = 20.3 °C

final temperature =  TO BE DETERMINED

<u>Step 2</u>: Calculate temperature

366000 J = 48000g * 4.184J/g °C * (T2 - 20.3)

366000 / (480000 * 4.184) = 1.8224 = (T2 - 20.3)

T2 = 20.3 + 1.82 =22.1224 ° C

The final temperature of water = 22.1224 °C

8 0
3 years ago
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