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erik [133]
3 years ago
7

a ball is thrown down from a building with an initial of 10 m/s and hits the ground with a velocity of 51 m/s how tall is the bu

ilding
Physics
1 answer:
olga55 [171]3 years ago
5 0

Answer:

41

Explanation:

you subtract the initial velocity which is 10m/s from the final velocity which is 51m/s

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A point from which the position of other objects can be described is called what?
Alisiya [41]

Answer:

Reference Point

Explanation:

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3 years ago
A baseball pitcher loosens up his pitching arm. He tosses a 0.20-kg ball using only the rotation of his forearm, 0.28 m in lengt
aev [14]

Answer:

Moment of Inertia, I = 0.016 kgm²

Explanation:

Mass of the ball, m = 0.20 kg

Length of the pitcher's arm, l = 0.28

Radius of the circular arc, r = 0.28 m

Moment of Inertia is given by the formula:

I = mr²

I = 0.20 * 0.28²

I = 0.20 * 0.0784

I = 0.01568

I = 0.016 kgm²

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3 years ago
When summer changes to fall, what seasonal changes do plants experience? (IGNORE HIGHLIGHTED ANSWER)
lorasvet [3.4K]

Answer:

C

Explanation:

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Please mark brainliest!!

*Quick Reminder: If this is an assignment from homeschool/school, please don't forget to rephrase/summarize/reference from this answer. Keep in mind no plagiarism is allowed in school. And please don't plagiarize this answer. Thanks!*

7 0
2 years ago
What is the purpose of a free body diagram?
leonid [27]

Answer:

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8 0
3 years ago
To calibrate the calorimeter electrically, a constant voltage of 3.6 V is applied and a current of 2.6 A flows for a period of 3
iren [92.7K]

Answer:

372.3 J/^{\circ}C

Explanation:

First of all, we need to calculate the total energy supplied to the calorimeter.

We know that:

V = 3.6 V is the voltage applied

I = 2.6 A is the current

So, the power delivered is

P=VI=(3.6)(2.6)=9.36 W

Then, this power is delivered for a time of

t = 350 s

Therefore, the energy supplied is

E=Pt=(9.36)(350)=3276 J

Finally, the change in temperature of an object is related to the energy supplied by

E=C\Delta T

where in this problem:

E = 3276 J is the energy supplied

C is the heat capacity of the object

\Delta T =29.1^{\circ}-20.3^{\circ}=8.8^{\circ}C is the change in temperature

Solving for C, we find:

C=\frac{E}{\Delta T}=\frac{3276}{8.8}=372.3 J/^{\circ}C

5 0
3 years ago
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