a ball is thrown down from a building with an initial of 10 m/s and hits the ground with a velocity of 51 m/s how tall is the bu
1 answer:
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Answer:
The displacement of the volleyball is 2.62 m
Explanation:
Given;
initial velocity of the volleyball, u = 7.5 m/s
final velocity of the volleyball, v = 2.2 m/s
displacement of the volleyball, d = ?
Apply the following kinematic equation;
v² = u² - 2gd
2gd = u² - v²
Therefore, the displacement of the volleyball is 2.62 m
Answer:
a
The orbital speed is
b
The escape velocity of the rocket is
Explanation:
Generally angular velocity is mathematically represented as
Where T is the period which is given as 1.6 days =
Substituting the value
At the point when the rocket is on a circular orbit
The gravitational force = centripetal force and this can be mathematically represented as
Where G is the universal gravitational constant with a value
M is the mass of the earth with a constant value of
r is the distance between earth and circular orbit where the rocke is found
Making r the subject
The orbital speed is represented mathematically as
Substituting value
The escape velocity is mathematically represented as
Substituting values