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LenaWriter [7]
3 years ago
10

Name the three main groups in

Chemistry
1 answer:
mel-nik [20]3 years ago
3 0

Answer:

element , gas , compound

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ratelena [41]
The answer is False
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3 years ago
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katovenus [111]
The tea was no longer hot or (brewed) so the 5th didn’t dissolve like the others because the tea was hot or warm enough anymore it cooled down. So the sugar won’t dissolve no more.
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3 years ago
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What volume in liters of carbon dioxide will be produced by the reaction of 18.5 liters of oxygen gas at STP?
agasfer [191]

Answer:

0.16 L

Explanation:

Step 1: Write the balanced equation

C₃H₈(g) + 5 O₂(g) → 3 CO₂(g) + 4 H₂O(g)

Step 2: Calculate the moles of CO₂ produced from 0.012 moles of O₂

The molar ratio of O₂ to CO₂ is 5:3. The moles of CO₂ produced are 3/5 × 0.012 mol = 0.0072 mol.

Step 3: Calculate the volume occupied by 0.0072 moles of CO₂ at standard temperature and pressure

At STP, 1 mole of CO₂ occupies 22.4 L.

0.0072 mol × 22.4 L/1 mol = 0.16 L

HOPE THAT HELP YOU mark me brinilylist

8 0
2 years ago
Which of the following is a property of an ionic compound?
11111nata11111 [884]

Answer:

C. Involves a metal and a nonmetal.

Explanation:

Ionic compound involves a metal and a non-metal. Ionic compounds have electrovalent bonds between them.

These compounds are usually made up of metals and non - metals combining to form a unit.

  • The metals usually has low electronegativity and transfers it electrons to the non - metal.
  • The non-metal has high affinity for the electron.
  • The electrostatic attraction between the ions formed results in the ionic bond.
6 0
3 years ago
Determine the energy of the electron in the 1s orbital of a helium ion (He+ )
Luda [366]
He Rydberg formula can be extended for use with any hydrogen-like chemical elements. 
<span>1/ λ = R*Z^2 [ 1/n1^2 - 1/n2^2] </span>
<span>where </span>
<span>λ is the wavelength of the light emitted in vacuum; </span>
<span>R is the Rydberg constant for this element; R 1.09737x 10^7 m-1 </span>
<span>Z is the atomic number, for He, Z =2; </span>
<span>n1 and n2 are integers such that n1 < n2 </span>
<span>The energy of a He+ 1s orbital is the opposite to the energy needed to ionize the electron that is </span>
<span>taking it from n = 1 (1/n1^2 =1) to n2 = ∞ (1/n2^2 = 0) </span>
<span>.: 1/ λ = R*Z^2 = 1.09737x 10^7*(2)^2 </span>
<span>λ = 2.278*10^-8 m </span>
<span>E = h*c/λ </span>
<span>Planck constant h = 6.626x10^-34 J s </span>
<span>c = speed of light = 2.998 x 10^8 m s-1 </span>
<span>E = (6.626x10^-34*2.998 x 10^8)/(2.278*10^-8) = 8.72*10^-18 J ion-1 </span>
<span>Can convert this value to kJ mol-1: </span>
<span>(8.72*10^-18*6.022 x 10^23)/1*10^3 = 5251 kJ mol-1 </span>
<span>Lit value: RP’s secret book: 5240.4 kJ mol-1 (difference is due to a small change in R going from H to He+) </span>
<span>So energy of the 1s e- in He+ = -5251 kJ mol-1</span>
6 0
3 years ago
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