Answer:
pplications of Pascal’s Law
Hydraulic Lift: The image you saw at the beginning of this article is a simple line diagram of a hydraulic lift. This is...
The construction is such that a narrow cylinder (in this case A) is connected to a wider cylinder (in this case B). They...
Pressure applied at piston A is transmitted equally to piston B without diminishing, on use of an incompressible fluid.
Explanation:
Answer:
The vector form is as shown in the attachment
Explanation:
The figure as shown in the diagram, indicates that the car is moving along the road at a constant speed. Centripetal acceleration comes into play for an object moving in a circular motion at uniform speed. The centripetal acceleration is the acceleration experienced by an object while in uniform circular motion.
Mathematically from centripetal acceleration; a = v2/r
The equation shows that there is an inverse relationship between the acceleration and the radius of curvature as such the radius of curvature at the point A will be more than the radius of curvature at the point C, this shows that the centripetal acceleration at point C will be more than the centripetal acceleration at point A.
The attachment shows the figure and the representation in vectorial form.
answer:
2.5 m/s²
Explanation:
120 km/h = 120 ÷ 3.6 = 100/3 ≈ 33 m/s
a = (v2 - v1)/∆t = (33m/s - 0)/ 13s = 33/13 m/s²≈ 2.5 m/s²
Because it has both magnitude and direction. When an object has positive acceleration, the acceleration occurs in the same direction as the movement of the object.
Answer:
Magnitude of electric field is 1.06 x
V/m along negative X-direction
Explanation:
Given: initial velocity of proton = u = 3.5 x
m/s
final velocity of proton = v = 0 m/s
initial point
= 0.2 m and final point is
= 0.8 m
According to conservation of energy:
change in in kinetic energy = change in potential energy of proton
⇒
where q and m is the charge and mass of proton E is the electric field ,
and
is the initial and final position of proton
on substituting the respected values we get,
1.023 x
= 9.6 x
x E
⇒ E = 1.06 x
V/m
external force is opposite to the motion as velocity of proton decreases with distance.
Therefore, magnitude of electric field is 1.06 x
V/m along negative X-direction