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3 years ago

How much time will it take for a bug to travel 2 meters across the floor if it is traveling at 0.5 m/s?

Physics

1 answer:

7nadin3 [17]3 years ago

6 0

4 seconds to travel 2 meters :)

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1 7.1.2 Quiz: Electrostatics

Veseljchak [2.6K]

Answer:

charge and distance

Explanation:

The electric force between the two particles are calculated using the formular:

F = kQ₁Q₂ / d²

where:

F = force.

k= Coulomb's law constant.

Q1 and Q2 are the charges.

d= distance.

the equation above is called Coulomb's law.

It can be seen from the equation above that the electric forces between the objects are majorly affected by the substance's charges and distance.

so the correct option is charge and distance.

5 0

2 years ago

Reese can run 10 meter in 5 seconds.What is her speed?

Bad White [126]

Answer:

2 meters per second

Explanation:

4 0

3 years ago

A 13 cm long tendon was found to stretch 3.7 mm by a force of 12.1 N . The tendon was approximately round with an average diamet

liq [111]

Answer:

young's modulus $=\frac{stress}{strain}=\frac{0.1990\times 10^{6}}{28.46\times 10^{-3}}=6.99\times 10^6N/m^2$

Explanation:

We have given length of tendon L= 13 cm =0.13 m

Change in length $\Delta L=3.7mm=3.7\times 10^{-3}m$

Force = 12.1 N

Average diameter d =8.8 mm

So $r=\frac{d}{2}=\frac{8.8}{2}=4.4mm=4.4\times 10^{-3}m$

Area $A=\pi\times (4.4\times 10^{-3})^2=60.79\times 10^{-6}m^2$

Now stress $=\frac{force}{area}=\frac{12.1}{60.79\times 10^{-6}}=0.1990\times 10^6N/m^2$

Strain $=\frac{change\ in\ lenght}{length}=\frac{3.7\times 10^{-3}}{0.13}=28.46\times 10^{-3}$

Now young's modulus $=\frac{stress}{strain}=\frac{0.1990\times 10^{6}}{28.46\times 10^{-3}}=6.99\times 10^6N/m^2$

8 0

3 years ago

He first step in treating drinking water called_______involv-es passing water through a series of screens

Taya2010 [7]

First filtration is the answer

6 0

3 years ago

Water flows along a streamline down a river of constant width. Over a short distance, the water slows from speed v to v/3. Which

kvasek [131]

Answer:

a. It became deeper by a factor of 3.

Explanation:

What we have is water flowing down a river with constant width. The water slows from speed v to v3 over a shirt distance

Using the equation of continuity

A1V1 = A2V2 ----1

A1 is the area of rectangle

V1 is the velocity of water

Area of rectangle = length x width

We rewrite equation 1 as

λ1w1v1 = λ2w2v2

We have w1 = w2

λ1v1 = λ2v2

λ1*v1 = λ2*v/3

λ1 = λ2/3

So it becomes deeper by a factor of 3

8 0

3 years ago