Write the skeleton equation: Cobalt and Sulfur react to produce Cobalt (II) Sulfide
1 answer:
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Answer:
Pentacarbon heptasilicide.
Explanation:
In order to name the following compound, we need to identify whether it is molecular or ionic.
Molecular compounds consist of non-metal atoms, while ionic compounds would have metal cations in their composition.
In the given compound, , we have two non-metals, carbon and silicon, meaning we should follow the molecular compound naming rules. The rules involve using prefixes to state the number of individual atoms.
The two prefixes required here are 'penta' for 'five' to indicate 5 carbon atoms present and 'hepta' for 'seven' to indicate 7 silicon atoms present.
The first part of the name would be pentacarbon (notice that the standard name for the first element is used). The second part would be heptasilicide (notice that the second atom would have an ending of -ide followed by the standard beginning of silicon).
Answer :
(a) The name for is titanium(IV) oxide.
(b) The name for is barium chloride.
(c) The name for is copper(III) chloride.
(d) The name for is potassium iodide.
(e) The name for is strontium chloride.
(f) The name for is copper(II) bromide.
Explanation :
Ionic compound : It is defined as the compound which is formed when electron gets transferred from one atom to another atom.
Ionic compound are usually formed when a metal reacts with a non-metal.
The nomenclature of ionic compounds is given by:
1. Positive ion is written first.
2. The negative ion is written next and a suffix is added at the end of the negative ion. The suffix written is '-ide'.
3. In case of transition metals, the oxidation state are written in roman numerals in bracket in-front of positive ions.
(a)
is an ionic compound because titanium element is a metal and oxygen element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.
The charge on tin is (+4) and the the charge on oxygen is (-2). Thus, the name for is titanium(IV) oxide.
(b)
is an ionic compound because barium element is a metal and chlorine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.
The charge on barium is (+2) and the the charge on chlorine is (-1). Thus, the name for is barium chloride.
(c)
is an ionic compound because copper element is a metal and chlorine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.
The charge on copper is (+3) and the the charge on chlorine is (-1). Thus, the name for is copper(III) chloride.
(d)
is an ionic compound because potassium element is a metal and iodine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.
The charge on potassium is (+1) and the the charge on iodine is (-1). Thus, the name for is potassium iodide.
(e)
is an ionic compound because strontium element is a metal and chlorine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.
The charge on strontium is (+2) and the the charge on chlorine is (-1). Thus, the name for is strontium chloride.
(f)
is an ionic compound because copper element is a metal and bromine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.
The charge on copper is (+2) and the the charge on bromine is (-1). Thus, the name for is copper(II) bromide.
Answer:
The classification and illustrations are attached in the drawing.
Explanation:
It is possible to identify the pure substance observing the figure, since it is the only one that has 2 joined atoms (purple and blue) which forms a single compound.
On the other hand, the homogeneous mixture is identified by noting that its atoms are more united with respect to the heterogeneous mixture, highlighting that in homogenous mixtures the atoms, elements or substances are not visible to the naked eye and are in a single phase, instead in the heterogeneous mixture if they can be differentiated.
