Answer:
Therefore it is save to carry a 62kg adult
Explanation:
From the question we are told that:
Mass ![m=380kg](https://tex.z-dn.net/?f=m%3D380kg)
Height of supporting Rock ![X=85cm](https://tex.z-dn.net/?f=X%3D85cm)
Length of Board![L_r=4.5m](https://tex.z-dn.net/?f=L_r%3D4.5m)
Mass of board ![M_b=22kg](https://tex.z-dn.net/?f=M_b%3D22kg)
Mass of adult
Generally the moment of balance about wedge part about is mathematically given by
![N -Q + R = Mg + mg](https://tex.z-dn.net/?f=N%20-Q%20%2B%20R%20%3D%20Mg%20%2B%20mg)
![0.85*N - Mg*2.25 - mg*(2.25 + x) = 0](https://tex.z-dn.net/?f=0.85%2AN%20-%20Mg%2A2.25%20-%20mg%2A%282.25%20%2B%20x%29%20%3D%200)
![0.85*N = + Mg*2.25 + mg*(2.25 + x)](https://tex.z-dn.net/?f=0.85%2AN%20%20%3D%20%2B%20Mg%2A2.25%20%2B%20mg%2A%282.25%20%2B%20x%29)
where
![N+R=4547](https://tex.z-dn.net/?f=N%2BR%3D4547)
therefore
![N = 570.70588 + 1608.3529 + 714.823 x](https://tex.z-dn.net/?f=N%20%3D%20570.70588%20%2B%201608.3529%20%2B%20714.823%20x)
if N=0 at fallen person
![x=3.04m](https://tex.z-dn.net/?f=x%3D3.04m)
Therefore it is save to carry a 62kg adult
Answer:
A stellar collision.
Explanation:
A stellar collision is the coming together of two stars caused by stellar dynamics within a star cluster, or by the orbital decay of a binary star due to stellar mass loss or gravitational radiation, or by other mechanisms not yet well understood.
Answer:
![T_2 = 77.5c](https://tex.z-dn.net/?f=T_2%20%3D%2077.5c)
Explanation:
From the question we are told that
Temp of first bolts![T_1=100](https://tex.z-dn.net/?f=T_1%3D100)
Temp of 2nd bolt ![T_2=55](https://tex.z-dn.net/?f=T_2%3D55)
Generally the equation showing the relationship between heat & temperature is given by
![q=cm \triangle T](https://tex.z-dn.net/?f=q%3Dcm%20%5Ctriangle%20T)
Generally heat released by the iron bolt = heat gained by the iron bolt
Generally solving mathematically
![-(0.45*m* (T_2-100 \textdegree c)) = 0.45*m*(T_2 -55\textdegree c)](https://tex.z-dn.net/?f=-%280.45%2Am%2A%20%28T_2-100%20%20%5Ctextdegree%20c%29%29%20%3D%200.45%2Am%2A%28T_2%20-55%5Ctextdegree%20c%29)
![-(T_2-100 \textdegree c)) = (T_2 -55 \textdegree c)](https://tex.z-dn.net/?f=-%28T_2-100%20%5Ctextdegree%20c%29%29%20%3D%20%28T_2%20-55%20%5Ctextdegree%20c%29)
![T_2 +T_2= 100 \textdegree c+55 \textdegree c](https://tex.z-dn.net/?f=T_2%20%2BT_2%3D%20100%20%5Ctextdegree%20c%2B55%20%5Ctextdegree%20c)
![T_2=\frac{155 \textdegree c}{2}](https://tex.z-dn.net/?f=T_2%3D%5Cfrac%7B155%20%5Ctextdegree%20c%7D%7B2%7D)
![T_2 = 77.5 \textdegree c](https://tex.z-dn.net/?f=T_2%20%3D%2077.5%20%5Ctextdegree%20c)
Therefore
is the final temperature inside the container
Answer:
![4.125\times 10^{-11}\ W/m^2](https://tex.z-dn.net/?f=4.125%5Ctimes%2010%5E%7B-11%7D%5C%20W%2Fm%5E2)
Explanation:
= Intensity of unpolarized light = ![1.1\times 10^{-10}\ W/m^2](https://tex.z-dn.net/?f=1.1%5Ctimes%2010%5E%7B-10%7D%5C%20W%2Fm%5E2)
= Angle of the filter = ![30^{\circ}](https://tex.z-dn.net/?f=30%5E%7B%5Ccirc%7D)
Intensity of light is given by
![I=\dfrac{I_0}{2}cos^2\theta\\\Rightarrow I=\dfrac{1.1\times 10^{-10}}{2}cos^230\\\Rightarrow I=4.125\times 10^{-11}\ W/m^2](https://tex.z-dn.net/?f=I%3D%5Cdfrac%7BI_0%7D%7B2%7Dcos%5E2%5Ctheta%5C%5C%5CRightarrow%20I%3D%5Cdfrac%7B1.1%5Ctimes%2010%5E%7B-10%7D%7D%7B2%7Dcos%5E230%5C%5C%5CRightarrow%20I%3D4.125%5Ctimes%2010%5E%7B-11%7D%5C%20W%2Fm%5E2)
The intensity of light detected by the camera is ![4.125\times 10^{-11}\ W/m^2](https://tex.z-dn.net/?f=4.125%5Ctimes%2010%5E%7B-11%7D%5C%20W%2Fm%5E2)
We can use the equation E = k | Q | r 2 E = k | Q | r2 to find the magnitude of the electric field. The direction of the electric field is determined by the sign of the charge,
<h3>What is electric and magnetic field ?</h3>
With the use of electricity and other types of artificial and natural illumination, invisible energy fields known as electric and magnetic fields (EMFs) and radiation are created.
- While the magnetic field is discernible by the force it exerts on other magnetic particles and moving electric charges, the electric field is actually the force per unit charge experienced by a non-moving point charge at any given location inside the field.
Learn more about Electromagnetic field here:
brainly.com/question/14372859
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