Answer:
The force required to move the quarterback with linebacker is <u>1215 N</u>
Explanation:
Using Newton's second law, it is established that F = Ma
Where F is net force acting on the system, a is the acceleration and M is mass of the two object 
Now consider both 
as a system, so net force acting on the system is 
Substitute the given values in the above formula,
Force = 1215 N
<u>1215 N </u>is the force required to move the quarterback with linebacker.
Usually nice weather , i dont know the answer to the second part
One of the main uses of this device is to test a beam of charged particles
What is cathode ray tube?
The cathode ray tube determines the charge flowing in a gas. When an electric field is set up using metal electrodes, the cathode ray tends to bend towards the positive electrode.
This concludes that a charge and the electrodes present helps determine the charge of the beam of charged particle.
Thus, one of the main uses of this device is to test a beam of charged particles.
Learn more about cathode ray tube.
brainly.com/question/1581574
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The solution for this problem is:torque1 = torque2 = FL / 2
Torque 3 = Torque 4 = FL / 2 * sin (theta)
Torque 5 = 2 FL
Torque 6 = 0
So the order of the torques from smallest to largest is torque 6, (torque 3 and 4), (torque 1 and 2), torque 5.
Remember or just take note that sin (theta) < 1 is why 3 and 4 are less than 1 and 2.
The perimeter of ΔWXY is : ( D ) 14.5 cm
<u>Calculating the </u><u>perimeter </u><u>of ΔWXY</u>
QR = WY / 2
RS = XW / 2
QS = XY / 2
Given that : QR = 2.93 cm , RS = 2.04 cm, QS = 2.28 cm
Therefore
Perimeter of ΔWXY = ∑ WY + XW + XY
= 2SR + 2QS + 2QR
= 2(2.04) + 2(2.28) + 2(2.93)
= 14.5 cm
Hence we can conclude that the perimeter of ΔWXY = 14.5 cm
learn more about perimeter calculations : brainly.com/question/24744445
