All categories

3 years ago

What is the pigment in the leaves called?

Physics

2 answers:

Angelina_Jolie [31]3 years ago

7 0

Answer: D: Chloroplasts

Explanation:

svet-max [94.6K]3 years ago

5 0

Answer: d

Explanation:

You might be interested in

Acceleration due to gravity is stated as a constant which is given 9.8 m/s2. Many scientists have planned and design experiments

stich3 [128]

The answer is 98.1 m/s2.

3 0

3 years ago

The distance, x, covered by a particle in time, t, is given as x=a +bc+ct^2 +dt^3

Sav [38]

Answer:

$a$ has units of distance

$b$ has units of distance over time

$c$ has units of distance over $time^2$

$d$ has units of distance over $time^3$

Explanation:

Since the expression for the distance is:

$x = a+b\,t+c\,t^2+d\,t^3$

then:

$a$ has units of distance

$b$ has units of distance over time

$c$ has units of distance over $time^2$

$d$ has units of distance over $time^3$

because we are supposed to be able to add all of the terms and get a distance. So the products on each term that contains factors of time (t) should be cancelling those time units with units in the denominator of the multiplicative constant s that accompany them.

6 0

3 years ago

Anyone know the answer ?

nata0808 [166]

Answer:

Explanation:

4 0

2 years ago

Read 2 more answers

Estimate (a) the maximum, and (b) the minimum thermal conductivity values (in W/m-K) for a cermet that contains 83 vol% carbide

velikii [3]

Answer:

k_max = 31.82 w/mk

k_min = 17.70 w/mk

Explanation:

a) the maximum thermal conductivity is given as

$k_{max} = k_m*v_m + k_p*v_p$

where k_m is thermal conductvitiy of metal

k_p is thermal conductvitiy of carbide

v_m = proportion of metal in the cement = 0.17

v_p = proportion of carbide in the cement = 0.83

= 66*0.17 + 28*0.83

k_max = 31.82 w/mk

b) the minimum thermal conductivity is given as

$k_{min} = \frac{k_{carbide}* k_{metal}}{k_{metal} v_{carbide} +k_{metal} v_{carbide}}$

= \frac{28+66}{28*0.17 +66*0.83}

k_min = 17.70 w/mk

7 0

3 years ago

Find the acute angles between the curves at their points of intersection. (The angle between two curves is the angle between the

ladessa [460]

Answer:

1.190390345 degrees.

Explanation:

As stated in the problem that the angle between the two curves is also the angle between slopes of the two cures at the point of intersection, which is 1 (when we set two equation equal and solve for x).

We know, if you don't you could verify it for yourself and it will be a nice mathematical exercise for you, that when there are two lines with slopes $m_1$ and $m_2$ then the angle between them and their two slopes has following relationship.

$tan(\alpha ) = |\frac{m_2-m_1}{1+m_1m_2}|$ where $\alpha$ is angle between the two lines.

As it is clear that we can easily get the angle between the two curves if we know slopes at that point, which you will see in second is very straight forward to calculate.

Slopes are simply derivatives evaluated at the point of intersection and the two derivatives are $D_1$ 16x and $D_2 =24x^2$ , substituting x =1 we get, $m_1 = 16$ and $m_2 = 24$ .

Now put $m_1$ and $m_2$ in this relationship, rearrange and solve for angle, it will come out to be

$\alpha$ = 1.190390345 degrees.

that is our angle that we want to know between the two cures at the point of their intersection.

3 0

3 years ago