Answer:
The length of the trail = 22796 ft
Explanation:
From the ΔABC
AC = length of the trail = x
AB = 6100 - 600 = 5500 ft
Angle of inclination = 15°
x = 22796 ft
Since x = AC = Length of the trail.
Therefore the length of the trail = 22796 ft
The flux through a surface is given by the scalar product of the field strength and the area
of the surface.
As the rectangular surface is in xy plane the flux corresponding to x and y component of
field will be zero (parallel to the surface) and the flux through the surface is only due to z
component of the field.
Because flux is the dot product of Electric field and area vector. So, parallel to surface is 0.
So,
The z component of the field is varying with x only and directly
proportional to x coordinate. (cx k)
Consider an infinitely thin strip of the surface at a distance x from y axis of thickness dx as
in figure. Field at this strip will have magnitude c*x and will be normal to the surface hence
the flux through this strip will be given by :
Because the Earth rotates through two tidal<span> “bulges” every lunar day, coastal areas experience<em> two </em></span><em>high</em><span><em> and two low </em></span><em>tides</em><span><em> every 24 hours and 50 minutes</em>.
</span>High tides occur<span> 12 hours and 25 minutes apart. It takes six hours and 12.5 minutes for the water at the shore to go from </span>high<span> to low, or from low to </span>high<span>.
I hope this helped!! Have an amazing day :))</span>
Answer:
(a)
vf_1s = 5.19 m/s
h_1s = 10.095 m
vf_4s = 24.23 m/s
h_4s = 4.49 m (below railing)
(b)
vi = 9.9 m/s
(c)
t = 1.53 s
h = 34.41 m
Explanation:
(c)
First, we will use the 1st equation of motion to find the time to attain the highest point:
where,
t = time to attain maximum height = ?
vf = final velocity = 0 m/s (ball momentarily stops at highest point
vi = initial velocity = 15 m/s
g = - 9.81 m/s (for upward motion)
<u>t = 1.53 s</u>
Now, for the height attained we will use the 2nd equation of motion:
<u>h = 34.41 m</u>
(b)
using the 3rd equation of motion for a height of 5 m:
<u>vi = 9.9 m/s</u>
<u></u>
(c)
At t = 1 s:
<u>vf_1s = 5.19 m/s</u>
<u></u><u></u>
<u>h_1s = 10.095 m</u>
<u></u>
At t = 4 s:
Since the ball covers the maximum height of 34.41 m in 1.53 s and then starts moving downward.
Therefore for the remaining 4 s - 1.53 s = 2.47 s, the initial velocity will be 0 m/s at the highest point and the value of g will be positive due to downward motion.
<u>vf_4s = 24.23 m/s</u>
<u></u><u></u>
now, for the position with respect to railing:
<u>h_4s = 4.49 m (below railing)</u>
<u></u>
The independent variable is how long the egg takes to cook