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zavuch27 [327]
3 years ago
9

900n pushes a wedge 0.10 m into a log, if the work done on the log is 50j what is the efficiency of the wedge

Physics
1 answer:
mariarad [96]3 years ago
7 0

Answer:

100

Explanation:

mark me brainliest

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Three samples of gas each exert 740. mm Hg in separate 2 L containers. What pressure do they exert if they are all placed in a s
Usimov [2.4K]
According to Dalton's law of partial pressure, the total pressure exerted is simply equal to the sum of the partial pressures of the individual gases. Given that all three samples of gas each exert 740 mmHg, when they are placed in a single 2 L container, they exert a pressure of 2220 mmHg on the container which is the sum of their individual pressures. 
5 0
3 years ago
Does a ball rolling on an inclined plane have the same acceleration on the way up as it does on the way down?
larisa86 [58]

Answer:

No, it does not.

Explanation:

According to the Law of Gravitation, something going down has more kinetic energy than something going up because it attracts pressure from around it when going down. When it goes up, it has less gravitational force and inertia also stops the ball from rolling upward. Therefore, without the amount of kinetic energy, it will not have the same amount of acceleration.

8 0
3 years ago
Metamorphic rocks are commonly formed at what kind of plate boundary?
DerKrebs [107]
 the answer is near the divergent plate boundary i think

5 0
3 years ago
A revolutionary war cannon, with a mass of 2090 kg, fires a 16.7 kg ball horizontally. The cannonball has a speed of 113 m/s aft
OLEGan [10]

Answer:

0.90291 m/s

0.45055 m/s

Explanation:

m_1 = Mass of canon = 2090 kg

m_2 = Mass of ball = 16.7 kg

v_1 = Velocity of canon

v_2 = Velocity of ball = 113 m/s

In this system the momentum is conserved

m_1v_1=m_2v_2\\\Rightarrow v_1=\dfrac{16.7\times 113}{2090}\\\Rightarrow v_1=0.90291\ m/s

The velocity of the cannon is 0.90291 m/s

Applying energy conservation

\dfrac{1}{2}m_1v_1^2+\dfrac{1}{2}m_2v_2^2=\dfrac{1}{2}m_2v^2\\\Rightarrow m_1v_1^2+m_2v_2^2=m_2v^2\\\Rightarrow v_2=\sqrt{\dfrac{m_1v_1^2+m_2v_2^2}{m_2}}\\\Rightarrow v_2=\sqrt{\dfrac{2090\times 0.90291^2+16.7\times 113^2}{16.7}}\\\Rightarrow v_2=113.45055\ m/s

The ball would travel 113.45055-113 = 0.45055 m/s faster

6 0
4 years ago
Which of the following best describes reverberation?
Liono4ka [1.6K]

Answer:

There are no appropriate descriptions on the list of choices you've provided.

Explanation:

Reverberation, in psychoacoustics and acoustics, is a persistence of sound after the sound is produced.[1] A reverberation, or reverb, is created when a sound or signal is reflected causing a large number of reflections to build up and then decay as the sound is absorbed by the surfaces of objects in the space – which could include furniture, people, and air.[2] This is most noticeable when the sound source stops but the reflections continue, decreasing in amplitude, until they reach zero amplitude.

4 0
3 years ago
Read 2 more answers
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