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olganol [36]
3 years ago
9

Consider the following fragment of code in an authentication program:

Engineering
1 answer:
Juli2301 [7.4K]3 years ago
8 0

Answer:

Backdoor

Explanation:

The back door fragment in a program allows user to access backdoor information without necessarily following the common security procedures needed. In this case, once the programmer keys in the username he or she logs in without putting password. Therefore, this is a backdoor fragment.

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A semiconductor is a solid substance that has a conductivity between that of an insulator and that of most metals. (True , False
tiny-mole [99]

The answer is : True

4 0
3 years ago
Initially when 1000.00 mL of water at 10oC are poured into a glass cylinder, the height of the water column is 1000.00 mm. The w
Dafna11 [192]

Answer:

\mathbf{h_2 =1021.9 \  mm}

Explanation:

Given that :

The initial volume of water V_1 = 1000.00 mL = 1000000 mm³

The initial temperature of the water  T_1 = 10° C

The height of the water column h = 1000.00 mm

The final temperature of the water T_2 = 70° C

The coefficient of thermal expansion for the glass is  ∝ = 3.8*10^{-6 } mm/mm  \ per ^oC

The objective is to determine the the depth of the water column

In order to do that we will need to determine the volume of the water.

We obtain the data for physical properties of water at standard sea level atmospheric from pressure tables; So:

At temperature T_1 = 10 ^ 0C  the density of the water is \rho = 999.7 \ kg/m^3

At temperature T_2 = 70^0 C  the density of the water is \rho = 977.8 \ kg/m^3

The mass of the water is  \rho V = \rho _1 V_1 = \rho _2 V_2

Thus; we can say \rho _1 V_1 = \rho _2 V_2;

⇒ 999.7 \ kg/m^3*1000 \ mL = 977.8 \ kg/m^3 *V_2

V_2 = \dfrac{999.7 \ kg/m^3*1000 \ mL}{977.8 \ kg/m^3 }

V_2 = 1022.40 \ mL

v_2 = 1022400 \ mm^3

Thus, the volume of the water after heating to a required temperature of  70^0C is 1022400 mm³

However; taking an integral look at this process; the volume of the water before heating can be deduced by the relation:

V_1 = A_1 *h_1

The area of the water before heating is:

A_1 = \dfrac{V_1}{h_1}

A_1 = \dfrac{1000000}{1000}

A_1 = 1000 \ mm^2

The area of the heated water is :

A_2 = A_1 (1  + \Delta t  \alpha )^2

A_2 = A_1 (1  + (T_2-T_1) \alpha )^2

A_2 = 1000 (1  + (70-10) 3.8*10^{-6} )^2

A_2 = 1000.5 \ mm^2

Finally, the depth of the heated hot water is:

h_2 = \dfrac{V_2}{A_2}

h_2 = \dfrac{1022400}{1000.5}

\mathbf{h_2 =1021.9 \  mm}

Hence the depth of the heated hot  water is \mathbf{h_2 =1021.9 \  mm}

4 0
3 years ago
ShoppingBay is an online auction service that requires several reports. Data for each auctioned item includes an ID number, item
daser333 [38]

Answer:

START

  READ ID_Number

  READ Item_description

  READ length_of_auction_Days

  READ minimum_required_bid  

  IF minimum_required_bid GREATER THAN 100

      THEN

          DISPLAY

              Item Details are

              Item Id : ID_Number

              Item Description: Item_description

              Length Action days: length_of_auction_Days

              Minimum Required Bid: minimum_required_bid

END

Explanation:

5 0
3 years ago
Hiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii
BartSMP [9]

Answer:

3. -9 degrees farenheit 5. Shes missing 3 cents. 6. 641 feet below sea level

Explanation:

3 0
3 years ago
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Design the software architecture for a student online registration system using the MVC architecture. Draw the architecture by s
Travka [436]

MVC architecture is defined as the architectural design that is used by software engineers for programming languages.

<h3>What are the various models of MVC architecture?</h3>

The various types of MVC architecture include the following:

  • The controller: This model is used to control logic and acts as the coordinator between the View and the Model.

  • The view: It displays the information from the model to the user.

  • The model: It is used to implement the domain logic.

Learn more about software here:

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