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3 years ago

In general, how can you increase the rate of a chemical reaction?

Physics

1 answer:

lesantik [10]3 years ago

3 0

Answer:

its 1

Explanation:

Several factors can increase the rate of a chemical reaction. In general, anything that increases the number of collisions between particles will increase the reaction rate, and anything that decreases the number of collisions between particles will decrease the chemical reaction rate.

Hope this helps? :))

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Vector ~A has a negative x-component 3.07 units in length and a positive y-component 3.17 units in length. When a vector ~B = b1

luda_lava [24]

Answer:

a. 3.07 b. 1.26

Explanation:

Given that A = -3.07i + 3.17j and B = b1i + b1j and C = A + B = 0i + 4.43j

Since A + B = -3.07i + 3.17j + b1i + b2j

= (-3.07 + b1)i + (3.17 + b2)j

So,(-3.07 + b1)i + (3.17 + b2)j = 0i + 4.43j

Comparing components,

-3.07 + b1 = 0 (1) and 3.17 + b2 = 4.43 (2)

a. From (1), b1 = 3.07

b. From(2) b2 = 4.43 - 3.17 = 1.26

4 0

3 years ago

The term _____ of energy means that the total amount of energy at the start and end of an energy transformation must be the same

Mnenie [13.5K]

I think is conversation

8 0

3 years ago

What is the direction of a vector with an x component of -12 m and a y component of -15 m?

dusya [7]

Answer:

$51.34^{\circ}$

Explanation:

Given that,

x component of a vector = -12 m

The y component of a vector = -15 m

We need to find the direction of a vector. The direction of a vector is given by :

$\tan\theta=\dfrac{y}{x}$

Put all the values,

$\tan\theta=\dfrac{-15}{-12}\\\\\theta=\tan^{-1}(\dfrac{-15}{-12})\\\\\theta=51.34^{\circ}$

So, the direction of vector is $51.34^{\circ}$ to x component.

3 0

3 years ago

5. How much time does it take for a bird flying at a speed of 45 kilometers per hour to travel a

Lyrx [107]

Answer:

$40h$

Explanation:

Use the velocity formula to solve

$v = \frac{d}{t}$

In this question, you are given velocity $v = 45km/h$ , and you are given a distance, $d = 1800km$ . Time in this question is what you'll need to find.

Start by rearranging the velocity formula, to isolate for t.

$v = \frac{d}{t}$

Start by multiplying both sides by t

$v(t) = \frac{d}{t}(t)\\\\vt = d$

Then divide both sides by v.

$vt\frac{1}{v} = d/v\\ \\t = \frac{d}{v}$

Now that you've isolated for time, sub in your values and calculate.

$t = \frac{d}{v} = \frac{1800km}{45km/h} = 40 h$

8 0

2 years ago

Competitive pressures stemming from the threat of entry are stronger when

navik [9.2K]

Answer:

Industries outlook is uncertain

Explanation:

Competitive pressures stemming from the threat of entry are stronger when the industry's outlook is uncertain or highly risky, entry barriers are low, and very few existing industry members are looking to expand their market reach by entering product segments or geographic areas where they currently do not have a presence. entry barriers are low, the pool of entry candidates is large, and existing industry members are earning good profits. there are fewer than 10 entry candidates with the potential to hurdle the industry's barriers to entry. t is difficult or costly for a customer to switch to a new brand, the total dollar investment needed to enter the market successfully exceeds $5 million, and existing governmental regulations impose significant cost and compliance burdens on industry members. buyers have strong brand preferences and high degrees of loyalty to their preferred brand and when it takes new entrants less than 5 years to secure attractive amounts of space on retailers' shelves and build a well-recognized brand name.

6 0

3 years ago