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3 years ago

An ocean wave travels at the surface between what two media?

Physics

2 answers:

Anon25 [30]3 years ago

6 0

Ocean waves travel at the surface between air and water.

Hope this helps!!! Please make brainliest!!!

Aleks04 [339]3 years ago

5 0

Answer: The correct answer is "air and water".

Explanation:

Ocean wave is a surface wave. It occurs at the surface of the ocean. Surface wave travels both parallel and perpendicular to the direction of the wave. The surface wave is neither transverse nor longitudinal wave.

Ocean wave is caused due to the motion of wind across the surface of water.

There is a friction between the water molecules and air molecules which causes energy to be transferred from wind to water.

Therefore, an ocean wave travels at the surface between air and water media.

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Two identical loudspeakers are some distance apart. A person stands 5.20 m from one speaker and 4.10 m from the other. What is t

Igoryamba

Answer:

125.09 Hz

Explanation:

Given : A person stands 5.20 from one speaker and 4.10 m away from the other speaker.

Distance between the speakers is 5.20 - 4.10 =1.10 m

We know that

For destructive interferences

n . λ / 2

where n =1,3,5,7....

Therefore difference between the speakers is

5.10 - 4.20 = 1 X 0.5 λ

λ = 2.2

Given velocity of sound is V = 344 m/s

Therefore frequency, f = $\frac{v}{\lambda }$

= $\frac{344}{2.2 }$

= 156.36 Hz

Now, the third lowest frequency is given by

λ = (5.20-4.10) X 5 X 0.5

= 2.75 m

Therefore frequency, f = $\frac{v}{\lambda}$

= $\frac{344}{2.75}$

= 125.09 Hz

Therefore third lowest frequency is 125.09 Hz

5 0

3 years ago

Two converging lenses, one with f = 4.0 cm and the other with f = 37 cm , are made into a telescope. What is the length of this

d1i1m1o1n [39]

Answer:

The length and the magnification of this telescope are 41 cm and 0.108.

Explanation:

Given that,

Focal length of first lens f= 4.0 cm

Focal length of other lens f'= 37 cm

We need to calculate the length of the telescope

Using formula of length

$L=f+f'$

Put the value into the formula

$L=4+37=41 cm$

We need to calculate the magnification of the telescope

Using formula of the magnification

$m=\dfrac{f}{f'}$

Put the value into the formula

$m=\dfrac{4}{37}$

$m=0.108$

Hence, The length and the magnification of this telescope are 41 cm and 0.108.

8 0

3 years ago

A dog sits 2.6 m from the center of a merry- go-round. a) If the dog undergoes a 1.7 m/s^2 centripetal acceleration, what is the

alexgriva [62]

Answer:

a) v= 2.1 m/s

b) ω = 0.807 rad/s

Explanation

Conceptual analysis :

The dog and the merry-go- round describes a circular motion, then, the following formulas apply :

$a_{c} =\frac{v^{2} }{r}$ Formula (1)

v = ω *r Formula (2)

Where:

$a_{c}$ : Centripetal acceleration(m/s²)

v: linear speed or tangential (m/s)

r : radius of the circle (m)

ω : angular speed ( rad/s)

Data

r= 2.6 m

$a_{c}$ = 1.7 m/s²

Problem develpment

a) We replace data in the formula 1 to calculate the dog's linear speed(v):

$a_{c} =\frac{v^{2} }{r}$

$1.7 =\frac{v^{2} }{2.6}$

$v^{2} =1.7*2.6 = 4.42$

$v=(\sqrt{4.42})\frac{m}{s}$

v= 2.1 m/s

b)We replace data in the formula 2 to calculate the angular speed of the merry-go- round (ω).

v = ω *r

2.1 = ω *2.6

ω = 2.1/2.6

ω = 0.807 rad/s

6 0

3 years ago

Water is flowing from a garden hose. A child places his thumb to cover most of those outlet, causing a thin jet of high speed wa

Oxana [17]

Answer: maximum height= 40.8m

Explanation: shown in the attachment.

Goodluck

3 0

2 years ago

A particle of mass m collides with a second particle of mass m. Before the collision, the first particle is moving in the x-dire

oee [108]

Answer:

a) v, v

b) 2mv^2

c) Elastic collion

Explanation:

(a) The velocity of the second particle after the collision is (v2x,v2y)=(v,−v). From momentum conservation in x-direction

Here x, y represent direction.They are not variable. 1 and 2 represent before and after.

2vm=v1xm+v2xm, we find v1x=v.

From momentum conservation in y-direction

0 =v1ym+v2ym, we findv1y=v.

(b) By energy conservation principle

Before: K=1/2m(2v)^2=2mv^2.

After: K=1/2m(v^2(1x)+v^2(1y))+12m(v22x+v22y)=2mv^2

6 0

3 years ago