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bogdanovich [222]
3 years ago
9

An ocean wave travels at the surface between what two media?

Physics
2 answers:
Anon25 [30]3 years ago
6 0

Ocean waves travel at the surface between air and water.

Hope this helps!!! Please make brainliest!!!

Aleks04 [339]3 years ago
5 0

Answer: The correct answer is "air and water".

Explanation:

Ocean wave is a surface wave. It occurs at the surface of the ocean. Surface wave travels both parallel and perpendicular to the direction of the wave. The surface wave is neither transverse nor longitudinal wave.

Ocean wave is caused due to the motion of wind across the surface of water.

There is a friction between the water molecules and air molecules which causes energy to be transferred from wind to water.

Therefore, an ocean wave travels at the surface between air and water media.

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You toss a walnut at a speed of 15.0 m/s at an angle of 50.0∘ above the horizontal. The launch point is on the roof of a buildin
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a.3.51s

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c. 9.64,-22.9

Explanation:

8 0
2 years ago
The instruction booklet for your pressure cooker indicates that its highest setting is 12.3 psi . you know that standard atmosph
zmey [24]
<span>118 C The Clausius-Clapeyron equation is useful in calculating the boiling point of a liquid at various pressures. It is: Tb = 1/(1/T0 - R ln(P/P0)/Hvap) where Tb = Temperature boiling R = Ideal Gas Constant (8.3144598 J/(K*mol) ) P = Pressure of interest Hvap = Heat of vaporization of the liquid T0, P0 = Temperature and pressure at a known point. The temperatures are absolute temperatures. We know that water boils at 100C at 14.7 psi. Yes, it's ugly to be mixing metric and imperial units like that. But since we're only interested in relative pressure differences, it's safe enough. So P0 = 14.7 P = 14.7 + 12.3 = 27 T0 = 100 + 273.15 = 373.15 And for water, the heat of vaporization per mole is 40660 J/mol Let's substitute the known values and calculate. Tb = 1/(1/T0 - R ln(P/P0)/Hvap) Tb = 1/(1/373.15 K - 8.3144598 J/(K*mol) ln(27/14.7)/40660 J/mol) Tb = 1/(0.002679887 1/K - 8.3144598 1/K ln(1.836734694)/40660) Tb = 1/(0.002679887 1/K - 8.3144598 1/K 0.607989372/40660) Tb = 1/(0.002679887 1/K - 5.055103194 1/K /40660) Tb = 1/(0.002679887 1/K - 0.000124326 1/K) Tb = 1/(0.002555561 1/K) Tb = 391.3034763 K Tb = 391.3034763 K - 273.15 Tb = 118.1534763 C Rounding to 3 significant figures gives 118 C</span>
3 0
3 years ago
If this decay has half-life of 2 years, how many years would it take for 10.8 g Protactinium-231 to remain given an initial mass
sergij07 [2.7K]

Answer:

Time = 6 years

Explanation:

First, we will calculate the no. of half life periods required to reduce the mass of Protactinium to the given value:

m' = \frac{m}{2^{n} } \\\\2^n = \frac{m}{m'}

where,

n = no. of half-life periods = ?

m = initial mass = 86.3 g

m' = remaining mass = 10.8 g

Therefore,

2^n = \frac{86.3\ g}{10.8\ g}\\\\2^n = 8\\2^n = 2^3

Since the bases are the same. Therefore equating powers:

n = 3

Now we calculate the time:

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<u>Time = 6 years</u>

3 0
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alukav5142 [94]

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Explanation:

7 0
3 years ago
As the Sun moves throughout the day, some plants can follow it. This is called _____.
Viefleur [7K]

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Explanation:

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6 0
2 years ago
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