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3 years ago

In what direction is the weight vector always drawn?

Physics

1 answer:

Varvara68 [4.7K]3 years ago

3 0

Yo sup??

The weight vector is usually drawn vertically downwards from the centre of the body.

It can be respectively resolved as well.

Hope this helps

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ziro4ka [17]

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A toxic relationship is the worst thing someone could have,because people need to learn to chill out.

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3 years ago

Ninas measurements shown in the table here BEST represent a wave with

Finger [1]

They best represent a wave with zero energy and zero amplitude.

There are no measurements shown in a table that accompanies
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2 years ago

Read 2 more answers

A large meteoroid enters the Earth's atmosphere at a speed of 20.0 km/s and is not significantly slowed before entering the ocea

Shalnov [3]

The shock wave from the meteoroid in the lower atmosphere has a Mach angle of 0.948°.

(a) The meteoroid's speed $v_s=20 \mathrm{~km} / \mathrm{s}$

$=20 \times 10^3 \mathrm{~m} / \mathrm{s}$

Air sound wave speed $&v=331 \mathrm{~m} / \mathrm{s} \\$

Speed of the shock wave in Mach $&\qquad \theta=\sin ^{-1}\left(\frac{v}{v_s}\right)$

$\begin{aligned}&=\sin ^{-1}\left(\frac{331 \mathrm{~m} / \mathrm{s}}{20 \times 10^3 \mathrm{~m} / \mathrm{s}}\right) \\&=0.948^{\circ}\end{aligned}$

Hence, 0.948° is the Mach angle of the shock wave from the meteoroid in the lower atmosphere.

<h3>What is the speed of the meteoroid?</h3>

A meteoroid's speed can be loosely broken down into three categories: slow, medium, and fast.

Slow meteors move around the sun at a leisurely pace of about 32 kilometers per second (20 miles per second).
Medium-speed meteors travel around the sun at approximately 50 kilometers per second (30 miles per second),
while fast meteors zoom past at over 120 kilometers per second (75 miles per second)!

To learn more about meteoroid, visit:

brainly.com/question/1939309

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1 year ago

A ball is tied to a string and whirled in a horizontal circle at a constant 4 revolutions per second. Categorize the following a

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2 years ago

If one-third of this energy goes into heat and other forms of internal energy of the motor, with the rest going to the motor out

Naily [24]

Answer

Assuming

electric motor consumes = 9.00 k J

electrical energy for time = 1.00 min

speed of engine = 2500 rpm

Power = $\tau_2\omega_2$