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Svetllana [295]

3 years ago

15

Physical quantities expresed only by their magnitude is

1 answer:

MrMuchimi3 years ago

8 0

Answer:

Scalar quantity is the Physical quantity expresed only by their magnitude.

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Frick and Frack are standing back-to-back, leaning on each other, but not moving. If Frick weighs

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Frick is pushing harder

Explanation:

if Frack weighs more and he was pushing harder they would be moving, but if Frick pushes harder then they wont move

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Look at a photograph of a fault. notice how the right side appears lower than the left side. this happens when pieces of crust a

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How many suns do you think are in our galaxy? Explain your answer PLS HELP ASP BEST GETS BRAINLIEST

dexar [7]

Answer: There is only one Sun in the galaxy … that is the thing that rises in the morning and sets at night. However, there is a use of “sun” to signify any old star … nobody knows exactly there might be trillions out there

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3 years ago

If m represent mass in kg, v represents speed in m/s and r represents radius in m show F in the formula F= (mv^2)/r can be expre

Dmitrij [34]

M <span>represent mass in kg
</span><span>v represents speed in m/s
</span><span>r represents radius in m

Now, just substitute these into the formula:
</span> $F = \frac{m* v^{2} }{r} =\frac{kg* ( \frac{m}{s} )^{2} }{m} =\frac{kg* \frac{m^{2}}{s^{2}} }{m} = \frac{kg*m^{2}}{s^{2}*m } =\frac{kg*m}{s^{2} }$ <span>

</span>

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3 years ago

a baseball is hit 3 feet above ground level at 100 feet per second and at an angle of 45 with respect to the ground. (g=32 feet/

LiRa [457]

Answer:

hmax=81ft

Explanation:

Maximum height of the object is the highest vertical position along its trajectory.

The vertical velocity is equal to 0 (Vy = 0)

$0=V_{y}-g*t=v_{0}*sin(\alpha)-g*th\\$

we isolate th (needed to reach the maximum height hmax)

$th = \frac{v_{0}*sin(\alpha)}{g}$

The formula describing vertical distance is:

$y = Vy * t-g* t^{2} / 2$

So, given y = hmax and t = th, we can join those two equations together:

$hmax = Vy* th-g*th^{2}/2$

$hmax =Vo^{2}*sin(\alpha )^{2}/(2*g)$

if we launch a projectile from some initial height h all you need to do is add this initial elevation

$hmax =h+Vo^{2}*sin(\alpha)^{2}/(2*g)$

$hmax =3+100^{2}*sin(45)^{2}/(2 * 32)=81 ft$

6 0

3 years ago