Is that all? That doesn’t help us give the answers
Answer:
1.024 x 10⁻²²g
Explanation:
Data Given:
mass of copper = 63.5 g
no. of atoms of copper = 6.02 x10²³ atoms
mass of of an average copper = ?
Solution:
As 6.02 x10²³ atoms have 63.5 g of mass then what will be the mass of atom.
Apply unity formula
63.5 g of copper ≅ 6.02 x10²³ atoms of copper
mass of copper atom ≅ 1 atom of copper
Do cross multiplication
mass of copper atom = 1 atom x 63.5 g / 6.02 x10²³ atoms
mass of copper atom = 1.024 x 10⁻²² g
mass of an average copper atom = 1.024 x 10⁻²² g
Answer:
The density (more precisely, the volumetric mass density; also known as specific mass), of a substance is its mass per unit volume. The symbol most often used for density is ρ (the lower case Greek letter rho), although the Latin letter D can also be used.
Answer:
30 atm
Explanation:
Initial Volume, V1 = 3L
Initial Pressure, P1 = 100 atm
Final Volume V2 = 10 L
Final Pressure, P2 = ?
These quantities are related by the Boyle's law equation which is given as;
V1P1 = V2P2
P2 = V1 * P1 / V2
P2 = 3 * 100 / 10
P2 = 30 atm
I think it might be C or D
