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Answer:
Bok.............................
Answer:
the maximum intensity of an electromagnetic wave at the given frequency is 45 kW/m²
Explanation:
Given the data in the question;
To determine the maximum intensity of an electromagnetic wave, we use the formula;
=
ε₀cE
²
where ε₀ is permittivity of free space ( 8.85 × 10⁻¹² C²/N.m² )
c is the speed of light ( 3 × 10⁸ m/s )
E
is the maximum magnitude of the electric field
first we calculate the maximum magnitude of the electric field ( E
)
E
= 350/f kV/m
given that frequency of 60 Hz, we substitute
E
= 350/60 kV/m
E
= 5.83333 kV/m
E
= 5.83333 kV/m × (
)
E
= 5833.33 N/C
so we substitute all our values into the formula for intensity of an electromagnetic wave;
=
ε₀cE
²
=
× ( 8.85 × 10⁻¹² C²/N.m² ) × ( 3 × 10⁸ m/s ) × ( 5833.33 N/C )²
= 45 × 10³ W/m²
= 45 × 10³ W/m² × (
)
= 45 kW/m²
Therefore, the maximum intensity of an electromagnetic wave at the given frequency is 45 kW/m²
Answer:
Explanation:
The former is the case of constructive interference and the later case relates to destructive interference.
For listener, path difference is the separation of loudspeaker as listener is not standing in between the speaker.
If λ be the wave length
For constructive interference
19 = n λ
For destructive interference
29 = (2n+1) λ / 2
= n λ + λ / 2
= 19 + λ / 2
10 = λ / 2
λ = 20 cm
= 0. 20 m
Answer:
a. 
b. Δ
c. 
Explanation:
a).
Momentum conserved





b).
Δ


Δ
c).


d).
All of which has been lost as mechanical energy, and is now thermal energy warmer football players, noise a loud crunch for example.