the titration is the most important part in determining whether
The mass of CO2 that would be produced is 144.03 g
From the equation of the reaction, the mole ratio of C2H4 input to CO2 produced is 1:2.
Recall that: mole = mass/molar mass
mole of 45.9 g C2H4 = 45.9/28.05
= 1.6364 moles
Thus: equivalent moles of CO2 = 1.6364 x 2
= 3.2727 moles
Mass of 3.2727 moles of CO2 = moles x molar mass
= 3.2727 x 44.01
= 144.03 g
More on stoichiometric calculations can be found here: brainly.com/question/8062886?referrer=searchResults
Answer:
You have to apply the base to an acid burn and vice versa.
Explanation:
The emission wavelength of the atoms excited above the ground state is 599.8 nm.
<h3>Emission wavelength of the atoms</h3>
The emission wavelength of the atom is determined by using the following formulas as shown below;
E = hf
E = hc/λ
where;
- E is the energy of the atom
- h is Planck's constant
- c is speed of light
- λ is the emission wavelength
λ = hc/E
λ = (6.626 x 10⁻³⁴ x 3 x 10⁸) / (3.314 x 10⁻¹⁹)
λ = 5.998 x 10⁻⁷ m
λ = 599.8 x 10⁻⁹ m
λ = 599.8 nm
Thus, the emission wavelength of the atoms is 599.8 nm.
Learn more about wavelength here: brainly.com/question/10728818
D. Experiments provided new evidence about the atom, I think, sorry if I’m wrong