Explanation:
Given that,
Rate of cooling of air
Initial temperature= 80°C
Final temperature = 5°C
We need to calculate
Using newton's law of cooling
Where,
Here,
= 25°C (surrounding temperature)
dt = 1 minute
Put the value into the formula
Hence, This is the required answer.
Answer:
r = 0.11 m
Explanation:
The radius of the proton's resulting orbit can be calculated equaling the force centripetal (Fc) with the Lorentz force (), as follows:
(1)
<u>Where:</u>
<em>m: is the proton's mass = 1.67*10⁻²⁷ kg</em>
<em>v: is the proton's velocity</em>
<em>r: is the radius of the proton's orbit</em>
<em>q: is the proton charge = 1.6*10⁻¹⁹ C</em>
<em>B: is the magnetic field = 0.040 T </em>
Solving equation (1) for r, we have:
(2)
By conservation of energy, we can find the velocity of the proton:
(3)
<u>Where:</u>
<em>K: is kinetic energy</em>
<em>U: is electrostatic potential energy</em>
<em>ΔV: is the potential difference = 1.0 kV </em>
Solving equation (3) for v, we have:
Now, by introducing v into equation (2), we can find the radius of the proton's resulting orbit:
Therefore, the radius of the proton's resulting orbit is 0.11 m.
I hope it helps you!