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vazorg [7]
3 years ago
6

4. Arrange the following from the smallest number of representative particles

Chemistry
1 answer:
Slav-nsk [51]3 years ago
4 0
A, C, D from smallest to largest
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when carbon is burned in the air, it reacts with oxygen to form carbon dioxide. when 22.8 g of carbon were burned in the presenc
OverLord2011 [107]

Answer:

So there is83.6g CO2 produced

Explanation:

Burning carbon with air has the following equation

C + O2 → CO2

For 1 mol Carbon, we have 1 mol O2 and 1 mol CO2

Step 2: Calculating moles

mole C = 22.8g / 12g/mole

Mole C = 1.9 mole

1.9 mole C will completely react

Since for each mole C there is 1 mole O2 and 1 mole CO2

This means there will also react 1.9 mole of 02, to be formed 1.9 mole of CO2

mole CO2 = mass CO2 / Molar mass CO2

mass CO2 = 1.9 mole CO2 * 44g/mole =<u>83.6g CO2</u>

In this reaction 18.2 g of O2 remained unreacted

we can control this: 79g - 18.2 g = 60.8g

1.9 mole * 32g/mol = 60.8g

So there is83.6g CO2 produced

4 0
3 years ago
Which of these is the final result of secondadry succession?
Grace [21]

Answer:

a

Explanation:

ADAPTATIOnn but if thhere would be an option o all the above it would be that

5 0
3 years ago
Read 2 more answers
SELECT ALL THAT APPLY
Luden [163]
The answer is 1 and 3. The number of atoms per molecule of these three substance is not equal. So they will not contain same number of atoms. And for gas, under same condition with same number of moles will have the same volume. The g.f.w is related to the atomic mass. So they are different.
8 0
4 years ago
Read 2 more answers
Which metal in Period 5 is very reactive and has two valence electrons in each atom? rubidium (Rb) strontium (Sr) zirconium (Zr)
vladimir1956 [14]
<h3>Answer:</h3>

           Strontium (Sr)

<h3>Explanation:</h3>

                        The condition given in statement is the presence of two valence electron. Hence, first we found the electronic configuration of given atoms as follow;

                       Rubidium                         [Kr] 5s¹

                      Strontium                        [Kr] 5s²

                       Zirconium                         [Kr] 4d² 5s²

                      Silver                                 [Kr] 4d¹⁰ 5s¹

From above configurations it is cleared that only Strontium and Zirconium has two electrons in its valence shell.

We also know that s-block elements are more reactive than transition elements due to less shielding effect in transition elements hence, making it difficult for transition metals to loose electrons as compared to s-block elements. Therefore, we can conclude that Strontium present in s-block with two valence electrons is the correct answer.

4 0
3 years ago
Read 2 more answers
How are salts formed?
patriot [66]

Explanation:

the process where the acids and bases neutralize each other to form salt and water is known as neutrilazation

6 0
3 years ago
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