Does anybody know how to answer any of these questions? Any of them without a check mark.

jeka94

Answer:

C.) Gravity

Explanation:

The projectile is an object upon which the only force is gravity. Gravity acts to influence the vertical motion of the projectile.

6 0

2 years ago

3 In a television tube, an electron starting from rest experiences a force of 4.0 × 10−15 N over a distance of 50 cm. The final

MAXImum [283]

Answer:

The final speed of the electron = 2.095×10⁸ m/s

Explanation:

From newton's fundamental equation of dynamics,

F = ma ........................Equation 1

Where F = force, m = mass of the electron, a = acceleration of the electron.

making a the subject of the equation,

a = F/m.................... Equation 2

Given: F = 4.0×10⁻¹⁵ N,

Constant: m = 9.109×10⁻³¹ kg.

Substituting into equation 2

a = 4.0×10⁻¹⁵/9.109×10⁻³¹

a = 4.39×10¹⁶ m/s².

Using newton's equation of motion,

v² = u²+2as .......................... Equation 3

Where v = final velocity of the electron, u = initial velocity of the electron, a = acceleration of the electron, s = distance covered by the electron.

Given: u = 0 m/s(at rest), s = 50 cm = 0.5 m, a = 4.39×10¹⁶ m/s²

Substituting into equation 3

v² = 0² + 2(0.5)(4.39×10¹⁶)

v = √(4.39×10¹⁶)

v = 2.095×10⁸ m/s

Thus the final speed of the electron = 2.095×10⁸ m/s

7 0

3 years ago

A sailboat weighing 980 lb with its occupants is running downwind at 8 mi/h when its spinnaker is raised to increase its speed.

Effectus [21]

Answer:

78.498N

Explanation:

The Net force provided by the spinnaker can be obtained from Newton's second law of motion as follows;

$F=\frac{m(v-u)}{t}................(1)$

where m is the mass, v is the final velocity, u is the initial velocity and t is the time interval for which the force acted.

Given;

m =980lb

v = 12mi/h

u =8mi/hr

t = 10s.

It is important to convert all quantities to their SI units where necessary, so we do that as follows;

1lb = 0.45kg,

hence 980lb = 980 x 0.45kg = 441kg.

1mile = 1609.34m

1hour = 3600s,

therefore;

$8mi/h=\frac{8*1609.34m}{3600s}=3.58m/s$

$12mi/h=\frac{12*1609.34m}{3600s}=5.36m/s$

Substituting all values into equation (1), we obtain the following;

$F=\frac{441(5.36-3.58)}{10}\\F=\frac{441*1.78}{10}\\F=\frac{784.98}{10}\\F=78.498N$

4 0

3 years ago

A spring is pulled to 10cm and held in place with a force of 500N. What is the spring constant of the spring

MrMuchimi

Answer:

5000

Explanation:

F=ke where f is the force, k is the spring constant, e is the extension....all in standard units

4 0

3 years ago

Read 2 more answers

What is the magnetic field at the center of a circular loop

Elan Coil [88]

Answer:

The magnetic field at the center of a circular loop is $3.14\times10^{-5}\ T$ .

Explanation:

Given that,

Radius = 4.0 cm

Current = 2.0 A

We need to calculate the magnetic field at the center of a circular loop

Using formula of magnetic field

$B = \dfrac{I\mu_{0}}{2r}$

Where, I = current

r = radius

Put the value into the formula

$B =\dfrac{2.0\times4\pi\times10^{-7}}{2\times4.0\times10^{-2}}$

$B =0.00003141\ T$

$B=3.14\times10^{-5}\ T$

Hence, The magnetic field at the center of a circular loop is $3.14\times10^{-5}\ T$ .

7 0

3 years ago