Answer:
a. Acceleration, a = 1.47 * 10^{-9} m/s²
b. Mass = 4.57 * 10^{10} kilograms
c. Force = 67.12 Newton
Explanation:
Given the following data;
Distance = 93 cm to meters = 93/100 = 0.93 meters
Weight = 67 N
Time = 9.89 hours to seconds = 35604 seconds
Initial velocity = 0 m/s (since it's starting from rest)
Acceleration due to gravity, g = 9.8 m/s
a. To find the acceleration, we would use the second equation of motion;
![S = ut + \frac{1}{2} at^{2}](https://tex.z-dn.net/?f=%20S%20%3D%20ut%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20at%5E%7B2%7D%20)
Where;
S is the distance covered or displacement of an object.
u is the initial velocity.
a is the acceleration.
t is the time.
Substituting the values into the equation, we have;
![0.93 = 0*35604 + \frac{1}{2} * a*35604^{2}](https://tex.z-dn.net/?f=%200.93%20%3D%200%2A35604%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20%2A%20a%2A35604%5E%7B2%7D%20)
![0.93 = 0 + \frac{1}{2} * 1267644816a](https://tex.z-dn.net/?f=%200.93%20%3D%200%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20%2A%201267644816a%20)
![0.93 = 633822408a](https://tex.z-dn.net/?f=%200.93%20%3D%20633822408a%20)
![Acceleration, a = \frac{0.93}{633822408}](https://tex.z-dn.net/?f=%20Acceleration%2C%20a%20%3D%20%5Cfrac%7B0.93%7D%7B633822408%7D%20)
Acceleration, a = 1.47 * 10^{-9} m/s²
b. To find the mass
Weight = mass * acceleration due to gravity
67 = mass * 1.47 * 10^{-9}
![Acceleration, a = \frac{67}{1.47 * 10^{-9}}](https://tex.z-dn.net/?f=%20Acceleration%2C%20a%20%3D%20%5Cfrac%7B67%7D%7B1.47%20%2A%2010%5E%7B-9%7D%7D%20)
Mass = 4.57 * 10^{10} kilograms
c. To find the force;
Force = mass * acceleration
Force = 4.57 * 10^{10} * 1.47 * 10^{-9}
Force = 67.12 Newton